12 !
Take the inverse cube root to get answer or to the 1/3 power:
1728^ (1/3) = 12
AB is 6
BC is 4
CD is 6
DA is 8
A is 45degrees
B is 130dgrees
C is 130degrees
D is 45degrees (about)
<u>Solving</u>
Knowing that we have the information needed we will first find the perimeter of the rectangle.
Rectangle:
Length: 13cm
Width: 7cm
Formula: L+L+W+W
13+13+7+7 = 40cm
Meaning the perimeter is 40cm and we can use this to find the length of a square. From general knowledge we know that all sides of a square is equal.
So if we divide the 4 sides by 40 we will get our answer.
40 ÷ 4 = 10
So B would be our answer...
<u>Statement</u>
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Therefore the length of a side of the square is 10cm, meaning answer B is correct.
3,000 yd3 = 200 dtl
Chapter 1: Problem Solving 17 / 21
Rates Question
12 A highway had a landslide, where 3,000 cubic yards of material fell on the road, requiring 200 dump truck loads to clear. On another highway, a slide left 40,000 cubic yards on the road. How many dump truck loads would be needed to clear this slide?
3,000 yd3 = 200 dtl
40,000 yd3 × 200 dtl = 2,667 dtl
3, 000 yd3
Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules