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Olegator [25]
3 years ago
14

I need help with this please help

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0

Answer:

Step-by-step explanation:

Hope fhat hep,ed skdnfsu. Soidhf scodfiysldm vij fhu idnvcmdlc

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1. You and 3 friends go out to Baskin and Robbins. Each buy ice cream for $5, a cookie = $3, and
igor_vitrenko [27]
4(5)+4(3)+3(2)=$38 total cost =$38
7 0
3 years ago
What is y=-2/3 x + 4 in standard form?
maxonik [38]

Answer:

2x + 3y = 12

Step-by-step explanation:

Standard form is Ax + By = C, A, B and C must be intergers, cannot be  fractions or decimals

y = -2/3x + 4 First we want to get rid of  the fractions.  There is only one, so if we multiply both sides by 3 that should do it.

3y = -2x + 12 Now make the constant be on one side by itself

2x + 3y = 12

5 0
3 years ago
Read 2 more answers
12 plus 2 times a number is 6 times the number. what is the number?
DedPeter [7]

Answer:

X=3

Step-by-step explanation:

12+2x=6x

7 0
3 years ago
Read 2 more answers
If a coin is tossed three times, find probability of getting
Assoli18 [71]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
1 year ago
Rectangle w/area of 91 has dimensions of (x+2) and (2x+3). Solve for dimensions.
Leviafan [203]

Answer:

5unit

Step-by-step explanation: since area of rectangle = length*width

Here length is (x+2) and width is(2x+3)

(x+2)(2x+3)=91

On further solving

2x^2+75x-85=0

2x^2-10x+17x-85=0

2x(x-5)+17(x-5)=0

(2x+17)(x-5)=0

x=5unit

8 0
3 years ago
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