Vb - Va = -366.7 V.
Vab = Va - Vb, the potential of a with respect to b, is equal to the work done by the electric force when a unit of charge moves from a to b, it is given by:
Vab = Va - Vb = Wab/q,
So, in order to determinate the potential difference Vb - Va we have to multiply by -1 both side of the equation above:
- (Va - Vb) = - (Wab/q)
Resulting
Vb - Va = -(Wab/q)
Given a positive charge q = 6.0μC = 6.0x10⁻⁶C, Wab = 2.2x10⁻³J. Determine Vb - Va.
Vb - Va = - (2.2x10⁻³J/6.0x10⁻⁶C)
Vb - Va = -366.7 J/C = -366.7 V
Answer:
The ratio is 0.667.
Explanation:
We are given two incandescent lights which have ratings of 75 W and 50 W .
Both bulbs operate at the same voltage.
The equation of power consumed is given by P =
Therefore the resistance for the 75 W bulb =
Therefore the resistance for the 50 W bulb =
Therefore the ratio of the resistance for the 75 W bulb to the resistance of the 50 W bulb is equal to
= = = 0.667.
The ratio is 0.667.
C=d(pi)=43.98in. Tip travels 3300 x C = 145,134in per min. (145,134in/min)(1ft/12in)(1 mile/5280ft)(60min/1 hr) = 137.4mph.