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3 years ago

A tow rope pulls a 1450 kg truck, giving it an acceleration 1.25 m/s^2. What force does the rope exert?

Physics

1 answer:

bagirrra123 [75]3 years ago

4 0

force=mass × acceleration

mass=force ÷ acceleration

acceleration=force ÷ mass

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What is the wavelength of an earthquake wave if it has a speed of 3 km/s and a frequency of 6 Hz?

disa [49]

Wavelength = c/f.
Wavelength =0.5km

8 0

3 years ago

how much force would be required to produce 88 j of work when pushing a box 1.1meters at an angle of 10 degrees?

ycow [4]

Answer:81.235N

Explanation:

Work=88J

theta=10°

distance=1.1 meters

work=force x cos(theta) x distance

88=force x cos10 x 1.1 cos10=0.9848

88=force x 0.9848 x 1.1

88=force x 1.08328

Divide both sides by 1.08328

88/1.08328=(force x 1.08328)/1.08328

81.235=force

Force=81.235

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3 years ago

When an automobile moves with constant speed down a highway, most of the power developed by the engine is used to compensate for

uysha [10]

Answer:

F=5449 N

Explanation:

Work done is a product of force and displacement ie

Work done, W, = Force*Displacement

Power, P, is Work done/Time

$P=\frac {W}{t}=\frac {FS}{t}$ where P is power, W is work done, F is force, S is displacement and t is time

In this case, F is the frictional force. Converting the power from hp to W, we multiply by 746 hence P=746*168=125328 W

Since displacement/time is velocity, then

P=FV where V is velocity in m/s

Making F the subject

$F=\frac {P}{V}$

$F=\frac {125328}{23}=5449.043478 N$

F=5449 N

7 0

3 years ago

The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energ

olya-2409 [2.1K]

Answer: 8400 J

Explanation:

The formula referenced in the question is:

$Q=m. c. \Delta T$

Where:

$Q$ is the thermal energy

$m=100g \frac{1 kg}{1000 g}=0.1 kg$ is the mass of the water sample

$c=4200 \frac{J}{kg\°C}$ is the specific heat capacity of water

$\Delta T=20\°C$ is the variation in temperature

Solving:

$Q=(0.1 kg)(4200 \frac{J}{kg\°C})(20\°C)$

$Q=8400 J$ This is the thermal energy released

8 0

3 years ago

A bobsled has a momentum of 3000 kg•m/s to the east. After the rider gives it a push, its momentum increases to 5500 kg•m/s to t

Archy [21]

Impulse, denoted as J, is defined by the change in momentum. Since we have our initial and our final, we can solve for the change in momentum.

$J = p_{f} - p_{0} = 5500 - 3000 = 2500

J = 2500 kg*m/s$

7 0

3 years ago

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