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Fynjy0 [20]
3 years ago
14

Tess ran 4 3 3 4 ​ start fraction, 4, divided by, 3, end fraction kilometers each day for 2 22 days. Cam ran 2 3 3 2 ​ start fra

ction, 2, divided by, 3, end fraction of a kilometer each day for 5 55 days. Who ran more kilometers in total? Choose 1 answer: Choose 1 answer: (Choice A) A Tess (Choice B) B Cam (Choice C) C They ran the same number of total kilometers. Stuck
Mathematics
1 answer:
mestny [16]3 years ago
7 0

We have been given that Tess ran \frac{4}{3} kilo-meters each day for 2 days.

Let us find total distance traveled by Tess in 2 days by multiplying \frac{4}{3} by 2 as:

\text{Distance traveled by Tess in 2 days }=\frac{4}{3}\times 2

\text{Distance traveled by Tess in 2 days }=\frac{4\times 2}{3}

\text{Distance traveled by Tess in 2 days }=\frac{8}{3}

We are also told that Cam ran  \frac{2}{3} kilo-meters each day for 5 days.

Let us find total distance traveled by Cam in 5 days by multiplying \frac{2}{3} by 5 as:

\text{Distance traveled by Cam in 5 days }=\frac{2}{3}\times 5

\text{Distance traveled by Cam in 5 days }=\frac{2\times 5}{3}

\text{Distance traveled by Cam in 5 days }=\frac{10}{3}

Since \frac{10}{3} km is greater than \frac{8}{3} km, therefore, Cam ran more kilo-meters in total and option B is the correct choice.

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How many of the first million positive integers share no common factors greater than 1 with 2020
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9514 1404 393

Answer:

  396,040

Step-by-step explanation:

Factors of 2020 are 2, 5, 101.

There are 1,000,000 / 1010 = 990 multiples of 2 and 5 and 101.

There are 1,000,000 / 505 -990 = 990 multiples of 5 and 101 only.

There are 1,000,000 / 202 -990 = 3,960 multiples of 2 and 101 only.

There are 1,000,000 / 10 - 990 = 99,010 multiples of 2 and 5 only.

There are 1,000,000 / 101 -990 -990 -3960 = 3,960 multiples of 101 only.

There are 1,000,000 / 5 -990 -990 -99,010 = 99,010 multiples of 5 only.

There are 1,000,000 / 2 -990 -3960 -99,010 = 396,040 multiples of 2 only.

So, the total number of multiples of any factor of 2020 is ...

  990 +990 +3960 +99,010 +3960 +99010 +396040 = 603960

Then the number of integers in the first million that do not share any common factors greater than 1 with 2020 is ...

  1,000,000 -603,960 = 396,040

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