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Fittoniya [83]
3 years ago
9

Help it’s 20 points!! Of a exit ticket!.

Mathematics
1 answer:
natka813 [3]3 years ago
7 0
X=1/2,-3 is the answer
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-6 is less than w, and w is less than 8
Mashutka [201]

Answer:

-6<w<8

Step-by-step explanation:

-6<w<8

6 0
3 years ago
g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, [ab]_H = [ba]_H . Since a and b were generic elements of H, then H/G is abelian.

4 0
3 years ago
PLEASE HELP THIS IS VERY IMPORTANT I'LL GIVE YOU BRAIN THING IF ITS CORRECT!! &lt;3 NO LINKS PLEASEE.
Nataly_w [17]

Answer and Step-By-Step Explanation:

The point shown is marked at (36,82), meaning that the panda is 36 months old and weighs 82 kilograms.  To plot the next point, just go up from 110 on the graph to 90 and mark a point.  (Sorry I tried to put an image but it was extremly blurry.)

7 0
3 years ago
Six years less than Tracy's age write it as a algebratic expression
docker41 [41]
 the answer would for the equation would beT-6 or 6-T
3 0
3 years ago
Read 2 more answers
The average daily volume of a computer stock in 2011 was ų=35.1 million shares, according to a reliable source. A stock analyst
Shtirlitz [24]

Answer:

a

   The  null hypothesis is  H_o :  \mu =  35 .1 \ million  \ shares

    The  alternative hypothesis  H_a  :  \mu  \ne  35.1\ million  \ shares

b

 The   95% confidence interval is  27.475   <  \mu < 37.925

Step-by-step explanation:

From the question the we are told that

      The  population mean is  \mu  = 35.1 \  million \ shares

      The  sample size is  n = 30

       The  sample mean is  \= x  =  32.7 \ million\    shares

       The standard deviation is  \sigma =  14.6 \ million\  shares

     

Given that the confidence level is  95\% then the level of significance is mathematically represented as

                  \alpha  = 100-95

                  \alpha  = 5\%

=>               \alpha  = 0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    The value is  Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

                 E  =  Z_{\frac{\alpha }{2} } *  \frac{ \sigma }{\sqrt{n} }

substituting values

                E  =  1.96 *  \frac{ 14.6 }{\sqrt{30} }

                E  =  5.225

The 95% confidence interval confidence interval is mathematically represented as

              \= x  -E  <  \mu <  \= x  +E

substituting values

               32.7 - 5.225   <  \mu < 32.7 + 5.225

                27.475   <  \mu < 37.925

       

6 0
3 years ago
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