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3 years ago

7

At a state fair, there are 10 animal exhibits, 12 gardening exhibits, and 8 farm equipment exhibits. Describe a model that you c

ould use to simulate randomly choosing an exhibit to visit.

1 answer:

12345 [234]3 years ago

6 0

Answer:

10:12:8

Step-by-step explanation:

so, there are 10 animal exhibits, 12 gardening exhibits, and 8 farm equipment exhibits. so it would look like this 10:12:8

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I need help ASAP!!!Please explain the answer

Stells [14]

Answer:

The formula for area is length times width.

it's 8m long, and 6m wide. When we multiply it, we get 48m that is for one side of the cube, so we count how many sides there is. There's 6, so we multiply 6 times 48 and the complete surface area for the whole cube is 288m

4 0

3 years ago

Given: The coordinates of rhombus WXYZ are W(0, 4b), X(2a, 0), YO, -4b), and Z(-2a, 0).

Shkiper50 [21]

Answer:

∴ MNOP is Rectangle

midpoint of XY (N) : (a , - 2b)

Step-by-step explanation:

W (0 , 4b) X ( 2a , 0) Y (0 , -4b) Z (-2a , 0)

M (midpoint of WX) : ( (0 + 2a)/2 , (4b + 0)/2) i. e. (a , 2b)

N (midpoint of XY) : ( (2a + 0)/2 , (0 - 4b)/2) i. e. (a , - 2b)

O (midpoint of YZ) : ( (0 - 2a)/2 , (- 4b + 0)/2) i. e. (- a , - 2b)

P (midpoint of ZW) : ( (0 - 2a)/2 , (4b + 0)/2) i. e. (- a , 2b)

MN: length = 2b + 2b = 4b MN segment perpendicular to x axis (slope undefined)

NO: length = a + a = 2a NO segment parallel to x axis (slope = 0)

OP: length = 2b + 2b = 4b OP segment perpendicular to x axis (slope undefined)

PM: length = a + a = 2a NO segment parallel to x axis (slope = 0)

MN = OP and MN // OP and MN ⊥ PM

NO = PM and NO // PM and NO ⊥ OP

∴ MNOP is Rectangle

midpoint of XY (N) : (a , - 2b)

please draw graph to prove

8 0

3 years ago

Find the equivalent expression 3p + 12m + 8

____ [38]

Answer:

3(p+4m) + 8

Step-by-step explanation:

Factor out a 3 for the first two terms, 3(p+4m) and add 8 like usual

6 0

3 years ago

Read 2 more answers

Given that f(x) = x + 3<br> a) Find f(2)

Nataly_w [17]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

In the above question, it is given that :

$\qquad \sf \boxed{ \sf f(x) = \frac{x + 3}{2} }$

A.) Find f(2) :

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{2 + 3}{2}$

$\qquad \sf \dashrightarrow \: f(2) = \dfrac{5}{2}$

or

$\qquad \sf \dashrightarrow \: f(2) = 0.5$

B.) Find ${ \sf {f}^{-1}(x) }$ :

$\qquad \sf \dashrightarrow \: let \: y = f (x)$

so, we can write it as :

$\qquad \sf \dashrightarrow \: y = \dfrac{x + 3}{2}$

$\qquad \sf \dashrightarrow \: 2y = x + 3$

$\qquad \sf \dashrightarrow \: x = 2y - 3$

Now, put x = ${ \sf {f}^{-1}(x) }$ , and y = x and we will get our required inverse function ~

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3$

C.) Find ${ \sf {f}^{-1}(12) }$ :

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 36- 3$

$\qquad \sf \dashrightarrow \: f {}^{ - 1}(12) = 33$

7 0

1 year ago

Frank and his family are going to the grand opening of a circus. There is a special price on tickets this weekend. Tickets cost

Art [367]

Answer:

30 dollars

Step-by-step explanation:

20% times 25

0.20 times 25= 5

25 + 5= 30

3 0

3 years ago