Answer:
the one on the left (the first one)
0.49 is the answer because that is <span>the approximate probability</span>
Step-by-step explanation:

from difference of two squares:

therefore:

factorise out ¾ :

Answer:
Option (1) will be the answer.
Step-by-step explanation:
Coordinates of the points A and B lying on the line f are (0, 2) and (2, 0) respectively.
Slope of the line f,


After dilation of line f by a scale factor of 2, coordinates of A' and B' will be,
Rule for dilation,
(x, y) → (kx, ky)
Where k = scale factor
A(0, 2) → A'(0, 4)
B(2, 0) → B'(4, 0)
Slope of line f',


Since, 
Therefore, both the lines f and f' will be parallel.
Option (1) will be the answer.