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NARA [144]
3 years ago
10

Find the area of the region bounded by the y-axis, x-axis and the line y=-2x+4.

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

The correct answer is 4

Anna007 [38]3 years ago
3 0

Answer:2

Step-by-step explanation:y = 0 : 0 = -2x + 4 → x = -2 is the x-intercept. Similarly, when the line crosses the y-axis, the x-coordinate at this point will be zero and substituting x = 0 into the equation will give us the y-intercept. x = 0 : y = 0 + 4 → y = 4 is the y-intercept.

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Answer:

he gets more money then he had to start with

Step-by-step explanation:

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The formula for the lateral area of a right cone is LA = rs, where r is the radius of the base and s is the slant height of the
Usimov [2.4K]

Answer:

The equivalent ratios are:

s = \frac{LA}{r}s=

r

LA

r = \frac{LA}{s}r=

s

LA

The formula LA = rsLA=rs is given

In order to determine the equivalent ratios, make r the subject of the formula and s the subject of the formula in the above equation

To make s, the subject of the equation, divide both sides of the equation by r

s = \frac{LA}{r}s=

r

LA

To make r, the subject of the equation, divide both sides of the equation by s

r = \frac{LA}{s}r=

s

LA

Step-by-step explanation:

the Answer is Above The Image Or The Answer box

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7 0
2 years ago
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If f(x) = 5x + 4, which of the following is the inverse of f(x)
MArishka [77]

Answer:

f^-1 (x)=1/5x-4/5

Step-by-step explanation:

y=5x+4

x=5y+4

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y=1/5x-4/5

4 0
3 years ago
Find the perimeter of the quadrilateral in simplest form A quadrilateral has side lengths of 2 StartRoot 27 EndRoot inches, Star
Katen [24]

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Step-by-step explanation:

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8 0
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Find the area of the shaded region. (You may express your answer in<br><br>terms of π.)
erastova [34]

Answer:

a. 16π cm²

b. 24π cm²

c. 33 1/3π cm²

d. 64π-128 cm²

e. 144π-288 cm²

Step-by-step explanation:

To find area of shaded region, find area of whole circle then divide the area where you're left with the area of the shaded region. For the problems with the triangles you find the area of the triangle then subtract that from a fourth of the area of the circle.

Area of a circle = πr²

a.

r=8cm

Area of circle=64π cm²

Shaded region=16π cm²

b.

r=12cm

Area of circle=144π cm²

Shaded region=24π cm²

c.

r=10cm

Area of circle=100π cm²

Shaded region=33 1/3π cm²

d.

r=16cm

Area of circle=256π cm²

Area of triangle=128 cm²

Shaded region=64π-128 cm²

e.

r=24

Area of circle=576π cm²

Area of triangle=288 cm²

Shaded region=144π-288 cm²

4 0
3 years ago
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