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Vesna [10]
3 years ago
9

SOLVE FOR X ANSWER IN FRACTION FORM I DONT NEED TO SHOW WORK​

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

x=\frac{27}{2}\:\text{or}\:13.5

Step-by-step explanation:

Both triangles are shown are similar. Therefore, the ratio of their sides will be maintained. We can then set up the following proportion:

\frac{2}{11}=\frac{3}{3+x},\\2(3+x)=33,\\(3+x)=16.5,\\x=\boxed{13.5\text{ or }\frac{27}{2}}

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$45 CD player 6% tax Calculate the total including tax, tip or markup. pls show work
Yanka [14]

Answer:

the tax would be $2.70

Step-by-step explanation:

FIrst you would make the tax in decimal form then multiply the decimal with the cost, then you wil get the tax

6 0
3 years ago
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Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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NEED ANSWER NOW!!
nydimaria [60]
The answer would be letter B. You can see that the price of the demanded products as the time passes by decreases. So the answer is letter B.
6 0
3 years ago
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Could you please help me to solve this query??
galina1969 [7]

Answer:

Show me problem

Step-by-step explanation:

I need a problem to solve it

3 0
3 years ago
Which of the following is an equation of the line that passes through the point (−2, 3) and is perpendicular to the graph of the
Ludmilka [50]

The equation of the line is y=-\frac{1}{3}+\frac{7}{3}

Explanation:

The given equation is y=3 x-2

<u>Slope:</u>

Since, the equation of the line is perpendicular to the equation y=3 x-2, then, the slope is given by

m=-\frac{1}{3}

Hence, the slope is m=-\frac{1}{3}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-2,3) and the slope m=-\frac{1}{3}, in the above formula, we get,

y-3=-\frac{1}{3}(x+2)

Simplifying, we get,

y-3=-\frac{1}{3}x-\frac{2}{3}

     y=-\frac{1}{3}x-\frac{2}{3}+3

     y=-\frac{1}{3}+\frac{7}{3}

Therefore, the equation of the line is y=-\frac{1}{3}+\frac{7}{3}

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