SOLVE FOR X ANSWER IN FRACTION FORM I DONT NEED TO SHOW WORK

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

5 0

Answer:

$x=\frac{27}{2}\:\text{or}\:13.5$

Step-by-step explanation:

Both triangles are shown are similar. Therefore, the ratio of their sides will be maintained. We can then set up the following proportion:

$\frac{2}{11}=\frac{3}{3+x},\\2(3+x)=33,\\(3+x)=16.5,\\x=\boxed{13.5\text{ or }\frac{27}{2}}$

You might be interested in

$45 CD player 6% tax Calculate the total including tax, tip or markup. pls show work

Yanka [14]

Answer:

the tax would be $2.70

Step-by-step explanation:

FIrst you would make the tax in decimal form then multiply the decimal with the cost, then you wil get the tax

6 0

3 years ago

Read 2 more answers

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.