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leva [86]
3 years ago
5

The sum of three consecutive numbers is eighty-four. Create the equation you would use to solve this problem using x as the vari

able for the first of the three consecutive numbers. (Do not use spaces)
Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

27,28,29

Step-by-step explanation:

x+x+1+x+2 =84

3x +3 =84

3x=84-3

3x=81

x=81 :3

x=27 (the first number

27 +1=28 (the second number

27 +2 =29 (the third number

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Example 2: Combining Use of the Multiplication and Addition Rules
bulgar [2K]

Answer:

The probability of getting 6's on both cubes is \frac{1}{36}.

The probability that the total score is at least 11 is \frac{1}{12}.

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is \frac{1}{6}

Probability of getting 6 on blue cube is \frac{1}{6}

Thus, the probability of getting 6's on both cubes is:

P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}

Hence, the probability of getting 6's on both cubes is \frac{1}{36}.

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}

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3 0
3 years ago
Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).
Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>
  • The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In this problem, the function is:

f(x) = x^3 + ax^2 + b

Hence, the derivative is:

f^{\prime}(x) = 3x^2 + 2ax

Then:

f^{\prime}(x) = 0

3x^2 + 2ax = 0

x(3x + 2a) = 0

x = 0

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3x = -2a

x = -\frac{2a}{3}

Since the critical point is at x = 2, we have that:

-\frac{2a}{3} = 2

-2a = 6

2a = -6

a = -3

Then:

f(x) = x^3 - 3x^2 + b

Critical point at (2,3) means that when x = 2, y = 3, then:

3 = 2^3 - 3(2)^2 + b

8 - 12 + b = 3

b = 7

You can learn more about the critical point concept at brainly.com/question/2256078

4 0
2 years ago
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