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Papessa [141]
3 years ago
8

(3x3 + 11x2 + 4x + 1)/ (x2 + x)

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0
If those are exponents, then...

3x^3 + 11x^2 + 4x + 1
-----------------------------               Cancel out the 11x^2 with the x^2
          x^2 + x

3x^3 + 10x^2 + 4x +1
-----------------------------               Cancel out the x with the 4x
                 x

3x^3 + 10x^2 + 3x +1
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Y is inversely proportional to the square of (x + 2).<br>When x = 3, y = 2.<br>Find y when x = 8.​
VikaD [51]

Answer:

y = k/(x+2) squared

substitute y and x to find the value of k.

k =50

nxt used the value of k with same formula:.

y= 50/ (8+2) squared

y =1/2

6 0
2 years ago
Emily is 2 years older than Alysson. The product of their age is 440. How old are they?
Nuetrik [128]
Call Emily's age is x, we have:
x * (x - 2) = 440
So x = 22
So Emily's 22 years old, Alysson's 20 years old.\\
Brainliest?
5 0
3 years ago
What is the volume of the triangular prism? Round to the nearest tenth.
Alex17521 [72]

Answer:

1,185.6 in.

Step-by-step explanation:

volume of the triangular prism = base area x height

the base in the shape of a triangle

area of a triangle = 1/2 x base x height

1/2 x 12 x 10.4 = 62.4 in²

volume = 62.4 x 19 = 1185.6 in

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

4 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
What is the negation of this statement x+y 10?
andre [41]
I'm not sure what your statement is.
Is it x+y = 10?

Because if it is, the negation of this statement would simply be x+y<span>≠10, which stands for not equal. </span>
7 0
3 years ago
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