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horsena [70]
2 years ago
14

BRAINLIEST

Mathematics
1 answer:
Cloud [144]2 years ago
3 0

10 ways I think if its wrong I'm sorry

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(8-16) + (8 + 6)
Furkat [3]

Step-by-step explanation:

Right now, we would solve everything within the parenthesis first.

(8 - 16) + (8 + 6)

(-8) + (14)

14 - 8

6

But if we remove the parenthesis, it doesn't matter what order we do things in.

8 - 16 + 8 + 6

8 + 8 - 16 + 6

16 - 16 + 6

6

The reason why both of these are the same, is because the only calculations we're doing are addition and subtraction, which don't care about parenthesis.

Answer:

A

7 0
2 years ago
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PLS HELP, WILL GIVE BRAINLIEST!
KonstantinChe [14]

Answer:

Step-by-step explanation:

5 0
2 years ago
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The price of apples is $3.60 for 3 pounds write the price as a unit rate
Finger [1]

Take the total and divide by the amount to get answer.

3.60 /3 = $1.20 per pound

4 0
3 years ago
Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f
GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that p = \frac{3}{4} = 0.75

Giannis shoots three free throws

This means that n = 3

What is the probability that he succeeds on at least two of them

P(X \geq 2) = P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219

P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438

84.38% probability that he succeeds on at least two of them

6 0
2 years ago
Complete the explanation of how you would shade a model to show 2 x 2/3
Alekssandra [29.7K]

Answer:

B.

Step-by-step explanation:

3 0
2 years ago
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