Help me find which is the mistake [will give brainliest and thanks}
1 answer:
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L=2w-3
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
w(2w-3)=54
2w²- 3w-54=0
A= 2 , B= -3, C= -54
sub values into quadratic formula
i attached picture of formula
Final answer: you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.
w=6
Check:
L=2w-3
=2(6)-3
=12-3
=9
9*6=54
Therefore the dimensions of the photograph are 6 cm by 9 cm
Solving for <em>Angles</em>
* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
Solving for <em>Edges</em>
You would use this law under <em>two</em> conditions:
- One angle and two edges defined, while trying to solve for the <em>third edge</em>
- ALL three edges defined
* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
_____________________________________________
Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:
- Two angles and one edge defined, while trying to solve for the <em>second edge</em>
- One angle and two edges defined, while trying to solve for the <em>second angle</em>
- ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]
* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.
I am delighted to assist you at any time.