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professor190 [17]
3 years ago
12

88) 4 times a number decreased by 8 equals 40 A) x=80 B) x = 40 C) x=8 D) x = 12

Mathematics
1 answer:
dimulka [17.4K]3 years ago
6 0
D=12
Because if you write down the equation 4x-8=40 and plug in 12. 4 times 12 is 48
. 48-8 equals 40
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What’s 1:6 equal too in two ways
IceJOKER [234]

Hey!

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Solution:

We can get two different ways of 1:6 by add +1:+6.

1 + 1 = 6 + 6

2:12

2 + 1 = 12 + 6

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Answer:

2:12 and 3:18

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Hope This Helped! Good Luck!

7 0
3 years ago
Whats 4(d+2)-2d=3(2+d)
Dmitry [639]

Simplify:

4(d + 2) - 2d = 3(2 + d)\\4d + 8 - 2d = 6 + 3d\\d + 8 - 2d = 6\\-d + 8 = 6\\-d = -2\\d = 2

d is equal to 2.

6 0
3 years ago
the boundary of a rectangular farm field in ireland has a straight rock wall along one side and fences along its other three sid
Inessa [10]

Answer:

781250 ft^{2}

Step-by-step explanation:

Let y is the length of the farm field

Let x is the width of the farm field

Given that, no fencing is necessary along the rock wall, so we can find the perimeter of the farm is:

2x + y = 2500 feet

<=> y = 2500 -2x

The are of the farm has the following formula:

A = x*y

<=> A = x(2500 - 2x)

<=> A = 2500x -2x^{2}

To have  the maximum area of field in square feet, we need to use differentials to estimate:

\frac{dA}{dx} = 2500 - 4x

Set \frac{dA}{dx} = 0, we have:

2500 - 4x  = 0

<=> x = 625 feet.

=> y = 2500 - 2*625 = 1250 feet

So the maximum area of field is:

A = x*y = 625*1250 = 781250 ft^{2}

7 0
3 years ago
A pencil factory makes 50 cases of pencils in 5 hours.
Oduvanchick [21]


If a pencil factory makes 50 cases of pencils in 5 hours. Let's first find out how many cases are made per hour.

50 ÷  5 = 10 cases per hour

Now you need to know how long it will take to make 55 cases. Since we already know that it takes 5 hours to make 50 cases. So you need to know how many cases for the extra 5 cases. If it takes 1 hour to make 10 cases, it would only take 1/2 hour to make 5 cases.

So it would take 5 1/2 hours to make 55 cases.

Hope this helps. :)

5 0
3 years ago
You borrow $5,000 from your parents to purchase a used car. The arrangements of the loan are such that you make payments of $250
AfilCa [17]
Part A:
1st month: Interest payable = 1% of $5,000 = $50.00
Amount paid in first month = $250 + $50.00 = $300
Unpaid balance = $5,000 - $250 = $4,750

2nd month: Interest payable = 1% of $4,750 = $47.50
Amount paid in second month = $250 + $47.50 = $297.50
Unpaid balance = $4,750 - $250 = $4,500

3rd month: Interest payable = 1% of $4,500 = $45.00
Amount paid in third month = $250 + $45.00 = $295.00
Unpaid balance = $4,500 - $250 = $4,250

4th month: Interest payable = 1% of $4,250 = $42.50
Amount paid in fouth month = $250 + $42.50 = $292.50
Unpaid balance = $4,250 - $250 = $4,000

5th month: Interest payable = 1% of $4,000 = $40.00
Amount paid in fifth month = $250 + $40.00 = $290.00
Unpaid balance = $4,000 - $250 = $3,750

6th month: Interest payable = 1% of $3,750 = $37.50
Amount paid in sixth month = $250 + $37.50 = $287.50
Unpaid balance = $3,750 - $250 = $3,500

7th month: Interest payable = 1% of $3,500 = $35.00
Amount paid in seventh month = $250 + $35.00 = $285.00
Unpaid balance = $3,500 - $250 = $3,250

8th month: Interest payable = 1% of $3,250 = $32.50
Amount paid in eighth month = $250 + $32.50 = $282.50
Unpaid balance = $3,250 - $250 = $3,000

9th month: Interest payable = 1% of $3,000 = $30.00
Amount paid in ninth month = $250 + $30.00 = $280.00
Unpaid balance = $3,000 - $250 = $2,750

10th month: Interest payable = 1% of $2,750 = $27.50
Amount paid in fouth month = $250 + $27.50 = $277.50
Unpaid balance = $2,750 - $250 = $2,500

11th month: Interest payable = 1% of $2,500 = $25.00
Amount paid in seventh month = $250 + $25.00 = $275.00
Unpaid balance = $2,500 - $250 = $2,250

12th month: Interest payable = 1% of $2,250 = $22.50
Amount paid in eighth month = $250 + $22.50 = $272.50
Unpaid balance = $2,250 - $250 = $2,000



Part B:
Number of payments = 5000 / 250 = 20
Total amount of interest = 50 + 47.5 + 45 + . . . + upto the 20th payment.
This is an arithmetic sequence with the first term as 50, common difference as -2.5 and number of terms = 20.

Sum of the first 20th term of the GP is given by
S_n= \frac{20}{2}[2(50)+(20-1)(-2.5)] \\  \\ =10(100-2.5(19))=10(100-47.5) \\  \\ =10(52.5)=\$525.00

Therefore, the <span>total amount of interest paid over the term of the loan is $525.00</span>
8 0
3 years ago
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