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Lisa [10]
3 years ago
7

Find the area of a circle with the radius of 73 feet

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

Step-by-step explanation:

area of a circle=πr^2

=3.14*(73)^2

=3.14*5329

=16733.06 ft^2

wariber [46]3 years ago
4 0

Answer:

A = 5329 pi ft^2

If we approximate pi with 3.14

A = 3.14*5329=16733.06 ft^2

If we use the pi button

A =16741.54725 ft^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

The radius is 73

A = pi ( 73) ^2

A = 5329 pi ft^2

If we approximate pi with 3.14

A = 3.14*5329=16733.06 ft^2

If we use the pi button

A =16741.54725 ft^2

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A $160 item is marked down 25%.what is the new cost of the item?
Sav [38]

$160 marked down 25% would be 40

8 0
3 years ago
Read 2 more answers
The domain and target set of functions f and g isR. The functions are definedas:(b)•f(x) = 2x+ 3•g(x) = 5x+ 7(a)f◦g?(b)g◦f?(c) (
adoni [48]

Answer:

Step-by-step explanation:

Given the domain and target set of functions f and g expressed as;

f(x) = 2x+3 an g(x) = 5x+7 we are to find the following;

a) f◦g

f◦g = f[g(x)]

f[g(x)] = f[5x+7]

To get f(5x+7), we will replace the variable x in f(x) with 5x+7 as shown;

f(x) = 2x+3

f(5x+7) = 2(5x+7)+3

f(5x+7) = 10x+14+3

f(5x+7) = 10x+17

Hence f◦g = 10x+17

b) g◦f

g◦f = g[f(x)]

g[f(x)] = g[2x+3]

To get g(2x+3), we will replace the variable x in g(x) with 2x+3 as shown;

g(x) = 5x+7

g(2x+3) = 5(2x+3)+7

g(2x+3) = 10x+15+7

g(2x+3) = 10x+22

Hence g◦f = 10x+22

c) For (f◦g)−1 (inverse of (f◦g))

Given (f◦g) = 10x+17

To find the inverse, first we will replace (f◦g) with variable y to have;

y = 10x+17

Then we will interchange variable y for x:

x = 10y+17

We will then make y the subject of the formula;

10y = x-17

y = x-17/10

Hence the inverse of the function

(f◦g)−1 = (x-17)/10

d) For the function f−1◦g−1

We need to get the inverse of function f(x) and g(x) first.

For f-1(x):

Given f(x)= 2x+3

To find the inverse, first we will replace f(x) with variable y to have;

y = 2x+3

Then we will interchange variable y for x:

x = 2y+3

We will then make y the subject of the formula;

2y = x-3

y = x-3/2

Hence the inverse of the function

f-1(x) = (x-3)/2

For g-1(x):

Given g(x)= 5x+7

To find the inverse, first we will replace g(x) with variable y to have;

y = 5x+7

Then we will interchange variable y for x:

x = 5y+7

We will then make y the subject of the formula;

5y = x-7

y = x-7/5

Hence the inverse of the function

g-1(x) = (x-7)/5

Now to get )f−1◦g−1

f−1◦g−1 = f-1[g-1(x)]

f-1[g-1(x)] = f-1(x-7/5)

Since f-1(x) = x-3/2

f-1(x-7/5) = [(x-7/5)-3]/2

= [(x-7)-15/5]/2

= [(x-7-15)/5]/2

= [x-22/5]/2

= (x-22)/10

Hence f−1◦g−1 = (x-22)/10

e) For the composite function g−1◦f−1

g−1◦f−1 = g-1[f-1(x)]

g-1[f-1(x)] = g-1(x-3/2)

Since g-1(x) = x-7/5

g-1(x-3/2) = [(x-3/2)-7]/5

= [(x-3)-14)/2]/5

= [(x-17)/2]/5

= x-17/10

Hence g-1◦f-1 = (x-17)/10

5 0
3 years ago
Un bidon con aguatiene capacidad para 63 litros si el bidon tiene llena la tercera parte de su capacidad total cuantos litros le
Zolol [24]

Answer:

42 litros

Step-by-step explanation:

63 / 3 = 21

21 * 2 = 42

6 0
3 years ago
Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,788 was collected on the sale of 1,260 ticket
blsea [12.9K]
Let x as number of adult tickets and y as number of student tickets

x+y=1260
y=1260-x

5x+1y=2688
5x+1(1260-x)=2688
5x+1260-x=2688
4x=2688-1260
x=1428÷4
x=357 adult tickets sold

y=1260-357
y=903 student tickets sold
6 0
4 years ago
A ball is projected upward from the ground. Its distance in feet from the ground in t seconds is given by s left parenthesis t r
julia-pushkina [17]

Answer:

t = 5.46 secs and t = 2.42 secs

Step-by-step explanation:

The distance of the ball from the ground is given by:

s(t) = -16t^2 + 126t

When the ball is at a distance 211 ft from the ground, that means s(t) = 211 ft. we need to find t:

211 = -16t^2 + 126t

=> 16t^2 -126t + 211 = 0

Using the quadratic formula:

t = \frac{-b + \sqrt{b^2 - 4ac} }{2a} and t = \frac{-b - \sqrt{b^2 - 4ac} }{2a}

where a = 16, b = 126 and c = 211

Hence:

t = \frac{-(-126) + \sqrt{(-126)^2 - 4(16)(211)} }{2(16)}     and          t = \frac{-(-126) - \sqrt{(-126)^2 - 4(16)(211)} }{2(16)}

t = \frac{126 + \sqrt{15876 - 13504} }{32}                     and           t = \frac{126 - \sqrt{15876 - 13504} }{32}

t = \frac{126 + \sqrt{2372} }{32}                                and           t = \frac{126 - \sqrt{2372} }{32}

t = \frac{126 + 48.703 }{32}                                and           t = \frac{126 - 48.703 }{32}

t = \frac{174.703}{32}                                     and           t = \frac{77.297}{32}

=> t = 5.46 secs and t = 2.42 secs

This means that the ball will be at 211 feet at two different times, first, after 2.42 seconds and then after 5.46 seconds.

This makes sense because the ball is projected upwards, which means that when going up, it attains 211 feet and also, when coming back down, it also attains 211 feet.

6 0
3 years ago
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