The slope of the line parallel to the points (3,-7) and (-6,5) is 
<u>Solution:</u>
We have been given two points of a line, and we have been asked to find the slope of a line parallel to it.
The given points are: (3,-7) and (-6,5)
According to the definition of parallel lines, two lines in a plane that do not intersect or touch each other at any point are said to be parallel.
And this is only possible if the two lines have the same slope.
Let the slope of the line be denoted by ‘m’.
So, to find the slope of the line given to us we do the following:
--- equation 1
Where y and x are coordinates of the points given to us.
Therefore substituting the values eq1 becomes:
Therefore the slope of the line is So by definition, the slope of a line parallel to this line will also have the slope
The straight line distance is 5 miles from starting point.
Step-by-step explanation:
Driving 3 miles north and 4 miles east and then the straight line distance will form a right angled triangle.
Where;
One leg = a = 3 miles
Other leg = b = 4 miles
Hypotenuse = c
Using Pythagoras theorem;
Taking square root on both sides
The straight line distance is 5 miles from starting point.
Answer:
4k^2-2k+4=-4 factor = 2(2k² -k +2) = -4
Step-by-step explanation:
She should have subtracted 6x from both sides to get -10x+11=1
1/2x + 3/4y = 4 ....multiply everything by 4
2x + 3y = 16
3y = -2x + 16
y = -2/3x + 16/3
In y = mx + b form, the slope will be in the m position and the y int will be in the b position
y = mx + b
y = -2/3x + 16/3
so ur slope is -2/3 and ur y int is (0,16/3)
