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Evgesh-ka [11]
3 years ago
13

What would be the range of possible measures of 5 and 6

Mathematics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

1

Step-by-step explanation:

vazorg [7]3 years ago
6 0
The answers would be 1
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SOMEBODY PLEASE HELP!! Find the missing value. Show your work please.
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What is the ratio of the area of the inner square to the area of the outer square?
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Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

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Now, the side of the outer square = Distance between the points (0,0) and (a,0),

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Thus, the area of the outer square = (side)²

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Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

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