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ollegr [7]
3 years ago
9

Solve the inequality 3x + 4 < 14​

Mathematics
1 answer:
Furkat [3]3 years ago
6 0
X right arrow ➡️ 6 hope this helped
You might be interested in
How many acres are in a rectangular field that measures 2310 ft by 535 ft?
valentina_108 [34]
Area = 2310 ft  *  535 ft = 1 235 850  ft²

43560 ft² = 1 acre.

1 235 850 ft² =   1 235 850/43560 ≈ 28.371 acres. 
4 0
3 years ago
Dr. Gonzalez is considering joining the Garden Club. If he pays a $25 membership fee, he
ziro4ka [17]

Answer:

In the Garden Club the cost will be a fixed fee of $25 and $10 for each rosebush, so if he buys X rosebushes, the total cost will be:

C1(X) = $25 + $10*X

While in the local nursery there is no initial cost, and each rosebush costs $15, so if he buys X rosebushes, the total cost will be:

C2(X) = $15*X

Now, let's find the value of X where C1 and C2 are equal, this is:

$25 + $10*X = $15*X

$25 = $15*X - $10*X = $5*X

X = 25/5 = 5

This means that if he buys 5 rosebushes, he will pay the same amount in both places.

If he buys less than 5 rosebushes, he will pay less in the local nursery (as it has a bigger slope, but no initial fee)

If he buys more than 5 rosebushes, he will pay less in the Garden club (because it has a smaller slope)

5 0
3 years ago
Jenny is comparing the cost of two packages of socks.One package has 8 pairs of socks for $12.Another package has 3 pairs of soc
EleoNora [17]

Answer:

  no

Step-by-step explanation:

The second package costs $2 for each pair of socks. If the first package cost that much, it would be 8×$2 = $16 for 8 pairs of socks. That is not the same as $12 for 8 pairs.

__

Another way to look at it is the first package costs twice as much as the second, but has more than twice as many pairs of socks. That means the rates are not equivalent.

6 0
3 years ago
Let Ebe the set of all even positive integers in the universe Zof integers, and XE : Z R be the characteristic function of E.
AnnZ [28]

Answer:

\mathbf{X_E (2) =  1}

\mathbf{X_E (-2) = 0 }  

\mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

Step-by-step explanation:

Let E be the set of all even positive integers in the universe Z of integers,

i.e

E = {2,4,6,8,10 ....∞}

X_E : Z \to R be the characteristic function of E.

∴

X_E(x) = \left \{ {{1 \ if  \ x \ \  is \ an \ element \ of \ E} \atop {0 \ if  \ x \ \  is \ not \ an  \ element \ of \ E}} \right.

For XE(2)

\mathbf{X_E (2) =  1}  since x is an element of E (i.e the set of all even numbers)

For XE(-2)

\mathbf{X_E (-2) = 0 }   since  - 2 is less than 0 , and -2 is not an element of E

For { x ∈ Z: XE(x) = 1}

This can be read as:

x which is and element of Z such that X is also an element of x which is equal to 1.

∴

\{ x \in Z: X_E(x) = 1\} = \{ x \in Z | x \in E\} \\ \\  \mathbf{\{ x \in Z: X_E(x) = 1\}  = E}

E = {2,4,6,8,10 ....∞}

5 0
3 years ago
Which is greater 34.653 or 3.4653?
Charra [1.4K]
34 is larger than 3, so 34.653
4 0
3 years ago
Read 2 more answers
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