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ollegr [7]
3 years ago
9

Solve the inequality 3x + 4 < 14​

Mathematics
1 answer:
Furkat [3]3 years ago
6 0
X right arrow ➡️ 6 hope this helped
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Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret messa
Tcecarenko [31]

The trigonometric function gives the ratio of different sides of a right-angle triangle. The given problems can be solved as given below.

<h3>What are Trigonometric functions?</h3>

The trigonometric function gives the ratio of different sides of a right-angle triangle.

\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°) = 3√3 / x

x = 3√3 / 3

W) For isosceles right-triangle, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3 = 4√3 / 3

S) Sin(60°) = x / (10/3)

x = 5√3 / 3

Learn more about Trigonometric functions:

brainly.com/question/6904750

#SPJ1

8 0
2 years ago
A model for the population p(t) in a suburb of a large city is given by the initial-value problem dp dt = p(10−1 − 10−7p), p(0)
irina1246 [14]

Answer:

T = 200 months

Step-by-step explanation:

Given the model to be

dp/dt = p(10-1-10-7p) where p(0) = 6000

dp/dt = p(-1-7p)

dp/dt = -p+7p²

But since P(0) = 6000

We plug this value into the equation

P = -6000+7(6000)²

P = -6000+252000000

P = 251994000. .limiting value

Differentiating dp/dt w.r.t p

dp/dt = -1+14p

dp'/dt = 14p-1

Plugging p(0) = 6000 into the above we have that

dp'/dt = 14(6000)-1

P' = 84000

Time population would be equal to 3/2 the limiting value

T = 3/2× 84000 = 126000

T = 25199400/126000

T = 199.99months

T = 200 months.

5 0
3 years ago
Read 2 more answers
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