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Alexxx [7]
3 years ago
6

Please Please help me

Mathematics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

1. 30

Step-by-step explanation:

First, place the numbers from least to greatest.

11,13,23,37,45,58

Then, find the middle number (or two middle numbers).

In this case, the middle numbers are 23 and 37.

Third, we find the mean of these numbers.

23+37=60

60/2=30

So your answer is 30.

Repeat this method for the other problems.

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Sever21 [200]
How old is sam? We need that first
8 0
3 years ago
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What are the answers since I’m confused an all over the place
dalvyx [7]
3 squares = 4 circles, so (number of squares)/(number of circles) = 3/4.
3/4 = 12/16
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4 squares = 2 circles, so (number of squares)/(number of circles) = 4/2.
4/2 = 2/1
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2 squares = 5 circles, so (number of squares)/(number of circles) = 2/5.
2/5 = 4/10

7 0
3 years ago
1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.
xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}

(If you were to plot the actual curve, you would have both y=x^{2/3} and y=-x^{2/3}, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx

We have

y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}

Then in the integral,

\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx

Substitute

u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx

This transforms the integral to

\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du

and computing it is trivial:

\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)

We can simplify this further to

\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}

7 0
3 years ago
How do you get the answer to 18,000 seconds = hrs?
Alex777 [14]
First you'd convert the seconds into minutes by dividing.

18,000 / 60 (60 secs in a min) = 300 minutes

Then, similarly,  you would convert the minutes into hours.

300 / 60 (60 mins in an hr) = 5 hours

The answer is 5 hours.
5 0
3 years ago
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Aye hello THIS IS FOR 30 POINT AND BRAINLIEST .
guajiro [1.7K]

If possible is to impossible then <u>certain</u> is to uncertain..

5 0
3 years ago
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