Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
Answer:25th Percentile: 5
50th Percentile: 30
75th Percentile: 34
Interquartile Range: 29
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Given that the segment is an angle bisector then the ratio of sides and base are equal, that is
= 
( cross- multiply )
10x = 72 ( divide both sides by 10 )
x = 7.2 → D
10 1/4 / 151 3/16 = 4/59
Have a great day :)
Answer:
4/5
Step-by-step explanation:
1/5*4 (given)
1/5*4/1 (add the one to make it a fraction)
4/5 (multiply straight across)
