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Stolb23 [73]
3 years ago
8

Implicit differentiation: ycosx=x^2+y^2

Mathematics
2 answers:
kramer3 years ago
6 0
Y cos x = x^2 + y^2 

Taking derivative:
<span>
y' cos x - y sin x = 2x + 2y y' </span>

Simplifying:

<span>y' = (- 2x - y sin x)/(2y - cos x)</span>
mixas84 [53]3 years ago
5 0

Answer:

Step-by-step explanation:

Given is an implicit function of y in x.

ycos x = x^2+y^2\\

The steps shown were the differentiation on both the sides

Left side done using product rule as well as chain rule and right side addition rule and chain rule

The steps got as

((y)(-sinx)+(cosx)(dy/dx)=2x+2y(dy/dx) is correct

Next step is to group all dy/dx terms together

cosx(dy/dx) - 2y(dy/dx) = ysinx+2x is also right step

Now rewrite left side as

\frac{dy}{dx} (cosx-2y)=2x+ysinx\\\frac{dy}{dx}=\frac{ysinx+2x}{cosx-2y}

Thus both the steps and answer are correct.

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Belle walks 7/10 mile each morning, and 1, 4/10 miles each evening.
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Answer:

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rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the heig
siniylev [52]
Consider this option:
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