Slope of a line that goes through the points (4,-1) and (3,8)
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Answer:
C)
region C
Step-by-step explanation:
We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:
0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]
0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]
So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.
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Answer:
see explanation
Step-by-step explanation:
Using the ratio equality for circles
=
(a)
Note the angle at the centre of the shaded arc is 360° - 90° = 270°, thus
=
=
( cross- multiply )
3C = 180 ( divide both sides by 3 )
C = 60 mm
(b)
Note the angle at the centre of the shaded arc is 360° - 135° = 225°, thus
=
( cross- multiply )
225C = 1188 ( divide both sides by 225 )
C = 5.28 cm