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Anna35 [415]
3 years ago
10

Find the surface area of the shape use NET

Mathematics
2 answers:
Snezhnost [94]3 years ago
6 0
I think it’s 100
Have an amazing day
irga5000 [103]3 years ago
5 0

Answer:

100

Step-by-step explanation:

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PLEASSSSSSE HELLOOPpppppppppp
liraira [26]
Volume of a rectangular prism is length * width * height. 

The figure can be broken into 3 different prisms. Left to right, I'd label them 1st tower, connecting base, 2nd tower. 

I'll do the 2nd tower first since it has the most measurements. 5 * 5 * 12 = 25 * 12 = 300

The first and second towers are congruent so they have the same measurements; we just do 300 + 300 to find their volumes. It's 600. 

Now, to find the connecting piece. The whole bottom length of this "U" shaped figure is 18 but the two towers have lengths of 5. To find the base of the portion we're looking for, we do 18 - 2(5) = 18 - 10 = 8. To find the height, we take away the top part of the second tower (7 m) from the whole height (12 m). 12 - 7 = 5. The width is given by the towers so we have what we need to solve. 

8 * 5 * 5 = 40 * 5 = 200

Now add the volumes all together. 

600 + 200 = 800

The figure has a volume of 800 cubic meters or 800 m³.
8 0
4 years ago
What is 3 to the power of 4
ladessa [460]
3 to the power of 4 is 81 
7 0
3 years ago
Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable.
Mashcka [7]

Answer:

Therefore the general solution is

2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Step-by-step explanation:

Integration Rule:

  1. \int x^n dx= \frac{x^{n+1}}{n+1}+c
  2. \int \frac1x dx= ln(x) +c

Given differential equation is

x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)

\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx    [ multiplying dx both sides]

\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx                [ dividing x^2\sqrt w both sides]

Integrating both sides

\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx

\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx

\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx

\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c   [ c is arbitrary constant]

\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Therefore the general solution is

2 \sqrt w = 2 ln(x) - 5 \frac1x +c

6 0
3 years ago
-6 x f(3) -6 x g(-1)​
AfilCa [17]

Answer:

-18F + 6g The exact value

4 0
3 years ago
You have to get everything on your list in 5 moves.<br> Can you do it?<br> Help please
MrRissso [65]

목록에있는 모든 것을 5 개의 동작으로 가져와야합니다.

5 0
3 years ago
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