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GarryVolchara [31]
3 years ago
9

The Data set shows the test scores for the mid-year exam for two different periods.

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0

answers:

I think it is 80

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The average attendance at school for 5 days was 264. If the attendance on the 5th day was 256, calculate the average attendance
Tema [17]

Answer:

266

Step-by-step explanation:

Let the attendence of 5days be a,b,c,d,e

given,

(a+b+c+d+e)/5=264

a+b+c+d+256=264*5 [since 5th day=256]

(a+b+c+d+)/4=1(320-256)/4 [dividing both side by 4]

average attendence of 4 days =266

5 0
3 years ago
I need help on combining like terms, they make no sense whatsoever. Here are the questions: y + 4 + 3(y+2)..........z^2 + z+ 4z^
vodomira [7]
Y + 4 + 3(y+2)
y + 4 + 3y + 3*2
4y + 4 + 6
4y + 10

z^2 + z+ 4z^3 + 4z^2
5z^2 + z + 4z^3

1/4 (16 + 4p)
16/4 + 4p/4
4 + p
5 0
3 years ago
What is the y intercept of the line containing the points shown in the table.
klemol [59]

Answer:

Answer is B

Step-by-step explanation:

In this question, we have to find the value of the y intercept and we have a table given .

First let's see what is y intercept.

y intercept is the value of y when x=0.

And in the given table , we have to check for the y value whose x value is 0 .

And when x=0, y=-5. THerefore y intercept is -5. And the correct option is B.

8 0
3 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ale4655 [162]

Answer:

0.8770

Step-by-step explanation:

We are dealing with a mean of a sample, so we use the formula

z=\frac{\bar{X}-\mu}{\sigma \div \sqrt{n}}

Our mean, μ, is 174.9 and our standard deviation, σ, is 35.2.  Our sample size, n, is 35.  To find P(X > 168),

z = (168-174.9)/(35.2÷√35) = -6.9/(35.2÷5.9161) = -6.9/5.9499 = -1.16

Using a z table, we see that the area under the curve to the left of this value is 0.1230.  However, we want the area to the right; this means we subtract from 1:

1-0.1230 = 0.8770

8 0
3 years ago
What is the area of a blanket that is 2.25 m long and 1.8 m wide
ioda
 The answer is 4.08. The reason is you have to multiply 2.25 and 1.8
4 0
4 years ago
Read 2 more answers
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