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3 years ago

What is the following product?

Mathematics

1 answer:

HACTEHA [7]3 years ago

6 0

Answer:

Step-by-step explanation:

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A miner has 3 kilograms of gold dust. She needs to share it evenly with four partners. How much gold should each of the five peo

djverab [1.8K]

600 g

Explanation:
Since 1 kilogram =1000 grams
Therefore 3 grams= 3000 grams
Now divide it with 5 partners
3000 divided by 5=600 grams

Each person will get 600 grams of gold dust

6 0

3 years ago

Determine if the events A and B are independent. Show all steps.

zmey [24]

Answer:

$P(A U B ) = \frac{13}{25}$

Step-by-step explanation:

STEP:-1

Given that events A and B are independent then

P(A ∩B ) = P(A) P(B)

Given that P(A) = 2/5 and P(B) = 1/5

STEP:- 2

P(A ∩B ) = P(A) P(B)

$P(A U B) = P(A) +P(B) - P(A n B )$

$P(A U B ) = P(A) +P(B) - P(A) P(B)$

Step(iii):-

$P(A U B ) = \frac{2}{5} +\frac{1}{5} - \frac{2}{5} X \frac{1}{5}$

$P(A U B ) = \frac{3}{5} - \frac{2}{5} X \frac{1}{5}$

$P(A U B ) = \frac{3}{5} - \frac{2}{25}$

$P(A U B ) = \frac{15-2}{25} = \frac{13}{25}$

4 0

3 years ago

I need help please ASAP

grin007 [14]

I’m pretty sure it is the first one

6 0

3 years ago

A bank loaned out $12,00, part of it at the rate of 9% per year and the rest at 19% per year. If the interest received in one

Crazy boy [7]

Answer:

$7,800 was invested at 9% and $4,200 at 19%.

Step-by-step explanation:

Given that a bank loaned out $ 12,000, part of it at the rate of 9% per year and the rest at 19% per year, if the interest received in one year totaled $ 1,500, to determine how much was loaned at 9% the following calculation must be performed:

12,000 x 0.09 + 0 x 0.19 = 1,080

10,000 x 0.09 + 2,000 x 0.19 = 1,280

8,000 x 0.09 + 4,000 x 0.19 = 1,480

7,900 x 0.09 + 4,100 x 0.19 = 1,490

7,800 x 0.09 + 4,200 x 0.19 = 1,500

Thus, $ 7,800 was invested at 9% and $ 4,200 at 19%.

6 0

3 years ago

Factor completely 16a^3b^7 + 2a^6b^4 - 22a^4b^5

Alina [70]

Answer:

$2a^3b^4(8b^3+a^3-11ab)$

Step-by-step explanation:

$as^3b^4(8b^3) +2a^6b^4-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)-22a^4b^5\\2a^3b^4(8b^3)+2a^3b^4(a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3)+2a^3b^4(-11ab)\\2a^3b^4(8b^3+a^3-11ab)$

4 0

3 years ago