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Norma-Jean [14]
3 years ago
10

Please please help me with this

Mathematics
2 answers:
zmey [24]3 years ago
6 0

Step-by-step explanation:

i think is k , m , l

bcause 4 is the smallest number,

and 12 is the biggest number.

inessss [21]3 years ago
3 0
I think it is K, M, and L
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Mrs. Regan went shopping and purchased 37 trees for the yard. ​Mr. Regan also went shopping and bought some trees. ​ ​If they ha
VikaD [51]

Answer:

45 trees

Step-by-step explanation:

82=37+M m=mr.regan

-37. -37

45=M

5 0
3 years ago
A. 55<br> b. 70<br> c. 110<br> d. 125
morpeh [17]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
The sum of two numbers is 10. twice the first number is 4 more than twice the second. what are the two numbers?
Ludmilka [50]
X+ y = 10
2x = 2y+4

2x/2 = 2/2y+4/2
x = y + 2

x+y = 10
y+2+y=10
2y + 2 = 10
2y +2-2 =10-2
2y = 8
2y/2 =8/2
y = 4

x + y =10
x + 4 =10
x +4-4 =10-4
x = 6

Check
2x = 2y +4
2(6) = 2(4) +4
12 = 8+4
12= 12
6 0
4 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
4 years ago
Find the probability for one roll of a standard number cube.
ArbitrLikvidat [17]

Answer:

\frac{1}{6}

Explanation:

Since there are 6 possible outcomes that number is the denominator. out of the six there is only one 5 on a standard number cube. So, there is a \frac{1}{6} possibility of rolling a 5. This fraction can't simplify so that is the answer.

3 0
4 years ago
Read 2 more answers
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