Answer:
C
Step-by-step explanation:
Dy/dx = y/x^2
1/y dy = 1/x^2 dx
int(1/y dy) = int(1/x^2 dx)
ln y + c1 = -x + c2
ln y = -x + c ; c= c2-c1
y = e^(-x+c) = e^c e^-x
y = Ce^-x ; C=e^c
Answer:
All
Explanation:
When an equation is in the form of y=kx, it displays direct variation, meaning that the y-intercept is 0. For example, take an equation in slope-intercept form, it has an equation of y=mx+b. Since there is no "b", in the form y=kx, that means that the line must pass through the origin, or (0,0)
