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Leokris [45]
2 years ago
6

What is the square root of ab^2 ?

Mathematics
2 answers:
Mandarinka [93]2 years ago
7 0

Answer:

B

Step-by-step explanation:

\sqrt{ab^2} = \sqrt{a}*\sqrt{b^2}  = \sqrt{a} * b = b\sqrt{a}

kap26 [50]2 years ago
5 0

Answer:

b\sqrt[n]{a}

Step-by-step explanation:

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Simplify the given expression. (16x^2 + 15xy – 19y^2) – (3x^2 – 3xy)
ruslelena [56]

Answer:

-19 y^2 + 18 x y + 13 x^2

Step-by-step explanation:

Simplify the following:

16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)

Factor 3 x out of 3 x^2 - 3 x y:

16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)

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16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2

Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):

-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)

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-19 y^2 + 18 x y + (16 x^2 - 3 x^2)

16 x^2 - 3 x^2 = 13 x^2:

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Find the mean of the following data set. 42, 45, 58, 63 42 47 52
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Step-by-step explanation:

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Answer:

A. 1/5k - 2/3j and -2/3j +1/5k

Step-by-step explanation:

A. 1/5k - 2/3j and -2/3j +1/5k

B. 1/5k - 2/3j and -1/5k +2/3j

There is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

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C. 1/5k - 2/3j and 1/5j - 2/3k

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1/5k changed to 1/5j

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D. 1/5k - 2/3j and 2/3j - 1/5k

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1/5k changed to -1/5k

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The only equivalent expression is

A. 1/5k - 2/3j and -2/3j +1/5k

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