Answer:
function
Step-by-step explanation:
Answer:
tex]a^2 - 4b \neq 2[/tex]
Step-by-step explanation:
We are given that a and b are integers, then we need to show that 
Let 
If a is an even integer, then it can be written as 
, then,
RHS is a fraction but LHS can never be a fraction, thus it is impossible.
If a is an odd integer, then it can be written as 
, then,
RHS is a fraction but LHS can never be a fraction, thus it is impossible.
Thus, our assumption was wrong and .
Nine tenths = 0.9
Twenty hundredths is 0.2
Two hundredths is 0.02
Forty five thousandths is 0.045
The number with the smallest value is 0.02, or two hundredths.
The inequality that correctly compares thirty five and thirty seven hundredths (35.37) to thirty five and ninety four thousandths (35.094) is B. 35.37 > 35.094, because 35.37 is greater than 35.094.
25 - [2 x (18÷ 6) + 1]
25 - [2 x (3) + 1]
25 - [6 + 1]
25 - [7]
18
25 - [2 x (18 ÷ 6) + 1] = 18
let "a number" = x
(x) + (x + 1) + (x + 2) = 72
Simplify. Combine like terms
3x + 3 = 72
Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.
3x + 3 (-3) = 72 (-3)
3x = 72 - 3
3x = 69
3x/3 = 69/3
x = 69/3
x = 23
23 is the smallest number
hope this helps
