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Nat2105 [25]
3 years ago
10

A rectangle has an area of 143 square meters and a width of 6. 5 meters. What is the length, l, of this rectangle? l = 121 m l =

78 m l = 65 m l = 22 m.
Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0
L = 22 because area equals length times width. So if you divide the area (143) by the width (6.5) you get 22
icang [17]3 years ago
4 0

Area of a rectangle is function of its length and width. The length of the specified rectangle is given by: Option D:  l = 22 m.

<h3>How does area of a rectangle, and its length and width are related?</h3>

Area of a rectangle is the product of its length and width.

If a rectangle has length L units and width of W units, then

Area = L × W squared units.

For the given case, it is specified that:

Area of considered rectangle = 143 square meters

Width of that same rectangle = 6.5 meters

Let its length be L meters.

Then,

A = L × W

143 =  L \times 6.5\\\\\text{Dividing both the sides by 6.5}\\\\\dfrac{143}{6.5} = L\\\\L = 22 \: \rm meters

Thus, The length of the specified rectangle is given by: Option D:  l = 22 m.

Learn more about area of rectangle here:
brainly.com/question/349091

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Where:

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e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }

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e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt

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The solution of the differential equation is:

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m_{salt} = V_{tank}\cdot c(t)

m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })

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