Step-by-step explanation:
Height of ladder = 12ft .
Here perpendicular is height to which it reaches .
<u>When </u><u>angle </u><u>is </u><u>3</u><u>0</u><u>⁰</u><u> </u><u>:</u><u>-</u>
=> sin 30⁰ = H/12
=> ½ = H/12
=> H = 12/2
=> H = 6m ( ans )
<u>When </u><u>Angle </u><u>is </u><u>4</u><u>5</u><u>⁰</u><u> </u><u>:</u><u>-</u><u> </u>
=> sin45⁰ = H/12
=> 1/√2 = H/12
=> H = 6*√2*√2/√2
=> H = 6√2 m ( ans )
<u>When </u><u>angle</u><u> </u><u>is </u><u>6</u><u>0</u><u>⁰</u><u> </u><u>:</u><u>-</u>
=> sin60⁰ = H/12
=> √3/2 = H/12
=> H = 12 *√3/2
=> H = 6√3 ( ans )
hope it helped !
The cost of 1 adult ticket in the off season is 42$, but it is asking for the child ticket's price so you would do 194-42 and you get 152. Then, you would divide 152/4 and you get 38 but this is during the off-season so you would double it and get 76.
The regular price for a child is 76$
But feel free to check my work :D
Answer:
Step-by-step explanation:
Decrease = 100 - 49 = 51
Percentage of decrease =

= 51%
Um, we see that the slice created the triangle, and the formula to find the area of the triangle:
1/2×B×h where B represent Base and h represent height.
In this case, Base=5 cm
Height=11 cm
A=1/2×11×5
A=5.5×5
A=27.5 square cm. As a result, the area of the resulting two-dimensional cross section is 27.5 square cm. Hope it help!
The functions are illustrations of composite functions.
<em>The soil temperature at 2:00pm is 67</em>
The given parameters are:
---- the function for sun intensity
-- the function for temperature
At 2:00pm, the value of h (number of hours) is:


Substitute 8 for h in
, to calculate the sun intensity



Substitute 8/9 for I in
, to calculate the temperature of the soil



Approximate

Hence, the soil temperature at 2:00pm is 67
Read more about composite functions at:
brainly.com/question/20379727