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3 years ago

7

The costs normally required to manufacture a product, which are calculated from historical costs and any changes from that, are

known as ____. standard costs abbreviated costs known costs estimated costs

1 answer:

bagirrra123 [75]3 years ago

7 0

a. standard costs is the correct answer

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As a factor of production, how is capital created? A. By adding land to entrepreneurship B. By adding human labor to land C. By

Dennis_Churaev [7]

Answer:

B

Explanation:

By adding human labor to land

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3 years ago

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Kanye, Jonny, Jaco, and Neil are trying to form a band. They each have some basic skills on most instruments, so their current p

Naddika [18.5K]

Answer:

2- Have each member specialize in the role that they are best in, to take advantage of benefits from specialization.

Explanation:

Here are the options

1- Continue with the current plan, as economies of scale should eventually kick in.

2- Have each member specialize in the role that they are best in, to take advantage of benefits from specialization.

3- Abandon the band, as continued practice is doomed to suffer diminishing marginal returns.

4- Invest their remaining savings in new instruments, as they are at a point where the marginal product of capital exceeds the marginal product of labor.

5- Change the rotation to be random rather than equal, to take advantage of heteroskedasticity.

Specialisation is when a person focuses on an activity in which they are efficient in or have a comparative advantage in

A person has a comparative advantage in production if he produces at a lower opportunity cost when compared to other people

Jaco seems to be efficient at playing bass, thus he should specialise in this activity

Jonny seems to be efficient at playing the guitar, thus he should specialise in this activity

An advantage of specialisation : Increased efficiency as a result of carrying out the same activity multiple time.

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2 years ago

suppose you invest $2250 in a CD that earns 3% APR and is compound quarterly. the cd matures in 2 years. how much will this cd b

Oksi-84 [34.3K]

Pn = P0(1+r)∧n

Pnis future value of P0

P0 is original amount invested

r is the rate of interest

n is the number of compounding periods (years, months, etc.)

P(n) = 2250(1+(.03/4)∧8

** since the interest is compounding quarterly, you need to divide the rate by 4, the number of quarters in a year.

Then you would do the math.

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3 years ago

Alicia has been keeping money in her room that she has earned from babysitting. What should Alicia do with this money?

Rudik [331]

A because then she can gain interest on her money

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3 years ago

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A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius

anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

$T^2 \alpha a^3$

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 $\times 10^8 \ km$

Therefore, $T^2 = ca^3$

$c= \dfrac{365^2}{(1.496 \times 10^8)^3}$

c = 3.9791 $\times 10^{20} \ day^2/km^3$

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

$T^2 = ca^3$

$a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}$

$a^3 = 2.9092 \times 10^{27}$

$a= \sqrt[3]{2.9092 \times 10^{27}}$

a = 1.4275 $\times 10^9 \ km$

However, the velocity for a perihelion = 10.18 km/s

Using the formula

$v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})}$ to calculate the radius, we have:

G = $6.674 \times 10^{-11}$

M = $1.989\times 10^{30} \ kg$

r = perihelion

$v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})$

$(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30} ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})$

$7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}$

$\dfrac{2}{r} = 1.4824 \times 10^{-12}$

$r = \dfrac{2}{1.4824 \times 10^{-12}}$

$r = 1.349 \times 10^{12}$

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

$1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)$

$1.349 \times 10^{12} - 1.425 \times 10^{12}= - 1.425 \times 10^{12} (e)$

$-7.6\times 10^{10}= - 1.425 \times 10^{12} (e)$

$\dfrac{-7.6\times 10^{10}}{- 1.425 \times 10^{12}}= (e)$

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

$r = 1.425 \times 10^{12} ( 1 + 0.0533)$

$r = 1.50 \times 10^{12} \ m$

to nautical miles, we have:

$r = 1.50 \times 10^{12} \times 0.00054 \ nautical \ mile$

radius of aphelion $\mathbf{r = 8.10 \times 10^8}$ nautical miles

In respect to the value of a( i.e $1.4275 \times 10^9 \ km)$

the body of the solar system is Saturn

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3 years ago