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Scrat [10]
3 years ago
11

Is this correct ? I need help

Chemistry
1 answer:
Volgvan3 years ago
5 0

Answer:

Yup, I believe so.

Explanation:

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What kind of oxide is formed when a piece of sodium is dropped in the water
aleksley [76]

Answer:

Sodium oxide is the product

Explanation:

4Na+O2->2Na2O

7 0
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____ are made up of solutes and solvents<br><br> A.Suspension <br> B.Colloid<br> C.Solutions
Sever21 [200]
I think it is A if wrong I’m sorry
7 0
3 years ago
Is (ch3)3N an acid, if s what kind strong, weak? or a base?
Lyrx [107]
Yes it is an acid and it is base
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The molecular weight of a gas is ________ g/mol if 3.5 g of the gas occupies 2.1 l at stp
bija089 [108]
<span>Pre-1982 definition of STP: 37 g/mol Post-1982 definition of STP: 38 g/mol This problem is somewhat ambiguous because the definition of STP changed in 1982. Prior to 1982, the definition was 273.15 K at a pressure of 1 atmosphere (101325 Pascals). Since 1982, the definition is 273.15 K at a pressure of exactly 100000 Pascals). Because of those 2 different definitions, the volume of 1 mole of gas is either 22.414 Liters (pre 1982 definition), or 22.71098 liters (post 1982 definition). And finally, there's entirely too many text books out there that still use the 35 year obsolete definition. So let's solve this problem using both definitions and you need to pick the correct answer for the text book you're using. First, determine how many moles of gas you have. Just simply divide the volume you have by the molar volume. Pre-1982: 2.1 / 22.414 = 0.093691443 moles Post-1982: 2.1 / 22.71098 = 0.092466287 moles Now determine the molar mass. Simply divide the mass by the moles. So Pre-1982: 3.5 g / 0.093691443 moles = 37.35666667 g/mol Post-1982: 3.5 g / 0.092466287 moles = 37.85163333 g/mol Finally, round to 2 significant figures. So Pre-1982: 37 g/mol Post-1982: 38 g/mol</span>
5 0
4 years ago
2H2 + O2 --&gt; 2H2OHow many moles of hydrogen gas are needed to produce 120g of water?
wlad13 [49]
<h2>Answer:</h2>

6.67moles

<h2>Explanations:</h2>

Given the balanced chemical reaction between hydrogen and oxygen expressed as:

2H_2+O_2\rightarrow2H_2O

First, you need to calculate the moles of water produced.

\begin{gathered} \text{Moles}=\frac{Mass}{\text{Molar mass}} \\ \text{Moles of water=}\frac{120}{2(1)+16} \\ \text{Moles of water}=\frac{120}{18} \\ \text{Moles of water}=6.67\text{moles} \end{gathered}

Based on stochiometry, 2 moles of hydrogen produces 2 moles of water, hence the moles of hydrogen that will be needed to produce 120g of water is 6.67moles

6 0
1 year ago
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