from an external source of power
Explanation:
The energy needed for nuclear fusion comes from an external source of power.
Nuclear fusion is the combination of small sized atomic nuclei to form larger ones.
The reaction releases a huge amount of energy but also requires a large activation energy to start up.
- The energy input require to drive two nuclei into fusion comes from an external source.
- Nuclear fusion has a high activation energy which serves as the energy barrier for this reaction to take place.
- The energy comes from the surrounding and once initiated, spontaneous chain reactions are set up.
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Answer:
Option C
Explanation:
The answer to this question will be the third option "It is bendable." Malleable means to be able to change the shape of a object without damaging or breaking it. In this case a malleable solid would be for example drainage pipes. These pipes have curves and different shapes but still remain its product of a metal.
Hope this helps!
Answer:
The correct option is B
Explanation:
One of the claims of John Dalton's atomic theory is that atom is the smallest unit of matter (which suggests that there are no particles smaller than an atom in any matter). This claim has been disproved by the modern atomic theory which established that there are particles smaller than atom (called subatomic particles). These particles are electrons, protons and neutrons.
One of the modern atomic theory was by Neils Bohr, who proposed that <u>electrons move in circular orbits around the central nucleus</u>. Thus, the electrons of iron can also be said to be present in a region of space (circular path) around the nucleus. This proves that option B is the correct option as John Dalton's theory did not even recognize the electron(s) nor the nucleus.
Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
Answer:
5.82 ×10⁴ j
Explanation:
Given data:
Mass of water = 25.7 g
Amount of heat to evaporate it = ?
Molar heat of vaporization = 4.07×10⁴ j/mol
Solution:
First of all we will calculate the number of moles of water.
Number of moles = mass/ molar mass
Number of moles = 25.7 g/ 18 g/mol
Number of moles = 1.43 mol
Energy needed for one mole is 4.07×10⁴ j.
For 1.43 mol:
1.43 mol × 4.07×10⁴ j/ 1mol
5.82 ×10⁴ j
