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Radda [10]
3 years ago
10

What is the answer????please helpp

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0
That answer is (0,0)
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Bert has 4 dogs and 5 cans of dog food.How much dog food does each dog get if Bert give each dog the same amount
Anettt [7]

Answer:

1.25 cans or 1 1/4

Step-by-step explanation:

5 divided by 4 = 1.25

5 0
3 years ago
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Can Someone Please Help I’ve been stuck on this question:(
otez555 [7]

Answer:

1.Yes

2.No

3.No

4.Yes

Step-by-step explanation:

7 0
3 years ago
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Mark scored 17 points for the home team in a basketball game. His teammates as a group scored p points. As a team they scored 46
ki77a [65]

Answer:

Equation:

17 + p = 46

His teammates scored 29 points

Step-by-step explanation:

We know that Mark scored 17 points and that the entire team scored 46.

Mark's 17 points added to the team's p points will give us a total of 46 points

p = points of his teammates

17 + p = 46

if we want to know how many points his teammates scored we simply have to clear p and solve

17 + p = 46

p = 46 - 17

p = 29

his teammates scored 29 points

3 0
4 years ago
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Divide £30 between 2 people in the ratio 1:2
yuradex [85]
1+2=3.
30/3=10
10x1=10
10x2=20
So the answer would be £10:£20
And to check if it’s right £10 + £20= £30
3 0
4 years ago
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Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ
Deffense [45]

Answer:

\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}

Step-by-step explanation:

Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}

\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16

\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i

6 0
3 years ago
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