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olasank [31]
3 years ago
9

4 times 1/3 (fraction form) will give brainlest

Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:

4/3

Step-by-step explanation:

I used a site and my calculator

You might be interested in
What is the denominator of the simplified expression? (startfraction 2 n over 6 n + 4 endfraction) (startfraction 3 n + 2 over 3
max2010maxim [7]

n/3n - 2.

The denominator of the given simplified expression is

The given expression is ( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 )

To find the denominator of the simplified expression :

First, simplify the given expression as below ;

( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 )

( 2n/2₍₃ₙ ₊ ₂₎ ( 3n + 2/ 3n - 2 )  ( here by taking the common term 2 outside the factor )

= (n/1) ( 1/ 3n - 2 ) ( here by simplifying the factors )

= n/3n - 2.

Therefore, ( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 ) = n/3n - 2

Therefore the result of the given simplified expression is = n/3n - 2.

Learn more about the simplified expression at

brainly.com/question/723406

#SPJ4

4 0
2 years ago
The following blank indicates a missing operation in the equation.
Natalija [7]
The answer would be 5/2q+9r+6r-20s

Explanation
We have the equation
5(1/2q+3r-4s)
which would equal
5/2q+15r-20s

so with the information
We can subtract 6r from 15r to get 9r
15r-6r=9r
+9r would be the missing piece

So we substitute it in to make the equation true.
5/2q(+9r)+6r-20s
Hope this helps or was correct
3 0
3 years ago
The ideal length of a particular metal rod is 30.5 cm. The measured length may vary from the ideal length by at most 0.015 cm. W
Oliga [24]

From 30.485 cm to 30.515 cm.

3 0
3 years ago
Read 2 more answers
Help for brainliest plz
VARVARA [1.3K]

Answer:

6/2 mark me as brainliest please

4 0
3 years ago
Pls help me factorize.Thanks!
Nat2105 [25]

We can change the sign of the second term, so that the two parenthesis are the same:

6(a-1)b^3+3(1-a)b^2 = 6(a-1)b^3-3(a-1)b^2

Now, both terms have in common a 3, becase the numeric factors are 3 and 6. If we factor the 3, we have

6(a-1)b^3-3(a-1)b^2 = 3(2(a-1)b^3-(a-1)b^2)

The parenthesis (a-1) is also in common, so we can factor it as well:

3(2(a-1)b^3-(a-1)b^2) = 3(a-1)(2b^3-b^2)

Finally, both terms in the parenthesis contain b^2, because it's the power of b with the lowest exponent:

3(a-1)(2b^3-b^2) =3(a-1)b^2(2b-1)

So, the factorization is

3b^2(a-1)(2b-1)

You can swap the order of the four factors (3, b^2, a-1 and 2b-1) as you like: the multiplication is commutative.

5 0
3 years ago
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