Drag each graph to show if the given data has a positive correlation, a negative correlation, or no correlation.

Mathematics

2 answers:

Arlecino [84]3 years ago

6 0

1 = positive
2 = no
3 = positive
4 = negative

Gemiola [76]3 years ago

3 0

Answer:

First graph = positive correlation

Second graph = no correlation

Third graph = positive correlation

Fourth graph = negative correlation

Step-by-step explanation: Correlation is the measure of how two or more variables are related to one another. Regarding the first and third graphs, the "y" variable tends to increase as the "x" variable increases, so the points seem to be going in an upward direction; therefore, these graphs represent a positive correlation. Regarding the fourth graph, the "y" variable tends to decrease as the "x" variable increases, so the points seem to be going in an downward direction; therefore, this graph represents a negative correlation. Regarding the second graph, the "y" variable tends to stay somewhat the same as the "x" variable increases, so the points seem to be going neither upwards nor downwards; therefore, this graph has no correlation.

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Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

$f(x)=x^3+2x^2-x-2$

The $y-intercept$ occurs when $x=0$ , so:

$f(0)=(0)^3+2(0)^2-(0)-2=-2$

Therefore, the $y-intercept$ is the given by the point:

$\boxed{(0,-2)}$

From the figure we have three $x-intercepts$ :

$\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}$

So, the $x-intercepts$ occur when $y=0$ . Thus, proving this:

$f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0$