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jeyben [28]
2 years ago
8

If f(x)=2xsquared+3x-2/x+2 is continuous at x=-2, then f (-2)=

Mathematics
1 answer:
Svet_ta [14]2 years ago
6 0
F(x) = (2x-1)(x+2)/ (x+2)
f(x) = 2x-1
f(-2) = 2(-2)-1
f(-2) = -5
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PLZ PLEASE OMG PLEASE
STatiana [176]

Answer:

N=N so b

Step-by-step explanation:

Because in LN=NP the reflexive property essentially takes this info and repeats itself N=N

6 0
2 years ago
I need help with this question
Alex787 [66]

Answer:

<h2>C</h2>

Step-by-step explanation:

using the pythagorian theorem, we know that a^2+b^2=c^2. inputting the numbers into this equation, we get

8^2+23^2=c^2

then, using our big math brains, we get 64+529=c^2

adding together the numbers, we end up with 593

just take the sqyare root of that and bada bing bada boom! you get 24.35, or 24.4, therefore the answer is C

3 0
2 years ago
If y = - 4/5x - 2, what is the value of x when y = - 9
MrRa [10]
Y = -4/5 x - 2
-9 = -4/5 x - 2
-4/5 x = -9 + 2 = -7
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x = -35/-4 = 35/4
3 0
3 years ago
Please hurry up .......
andre [41]

Answer:

I think the answer is D.

4 0
2 years ago
Read 2 more answers
a 5 inch tall bamboo shoot doubles in height every 3 days. if the equation, y=ab^x where x is the number of doubling periods, re
Lemur [1.5K]
X-doubling periods
Y-height of bamboo
Y=ab^x

1) make a table of values
X Y
1 5
2 10
3 20

2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2

Substitute into second equation

10=(5/b)*b^2
10=5b^2/b
10=5b
b=2

Substitute back in

b=2
10=a*2^2
10=4a
a=5/2

End equation:
Y=5/2*2^x


3 0
2 years ago
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