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2 years ago

What are the solution(s) to the quadratic equation 50 – X2 = 0?

Mathematics

2 answers:

Bezzdna [24]2 years ago

8 0

Answer:

$50 - {x}^{2} = 0 \\ {x}^{2} = 50 \\ x = \sqrt{50} \\ x = 5 \sqrt{2}$

romanna [79]2 years ago

5 0

Answer:

Step-by-step explanation:

50 - x² = 0

50 = x²

x² = 50

x = √50

$x = \sqrt{2*5*5}\\\\x=5\sqrt{2}$

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What is the area of the sector a.) 10π cm^2b.) 16π cm^2c.) 40π cm^2d.) 64π cm^2

Natalija [7]

Answer:

C. 40π cm²

Explanation:

• The central angle of the sector = 225 degrees

• The radius of the sector = 8cm

For a sector of radius r and central angle θ, we calculate the area using the formula below:

$\text{Area}=\frac{\theta}{360\degree}\times\pi r^2$

Substituting the given values, we have:

$\begin{gathered} \text{Area}=\frac{225}{360}\times\pi\times8^2 \\ =\frac{5}{8}\times64\times\pi \\ =5\times8\times\pi \\ =40\pi cm^2 \end{gathered}$

The area of the sector is 40π cm².

3 0

11 months ago

SOMEONE HELP ME OUT ASAP PLEASE

goldenfox [79]

Answer:

Step-by-step explanation:

because when you divide with the coeficient it sums out to be 7

7 0

2 years ago

Helpppppp me right now!

Rudik [331]

Answer:

B and D

7/12 cups

Step-by-step explanation:

2 1/3 + 2 1/4 = cups of flour needed

4 = cups of flour had

2 1/3 + 2 1/4

To have the same denominator, we take the lcm

2 + 2 + (4/12 + 3/12) =

2 4/12 + 2 3/12 - 4

2 + 2 + (3 + 4) / 12 - 4

2 + 2 + (3 + 4) / 12 - 4 = 4 7/12 - 4

4 7/12 - 4 = 7/12 cups of flour needed

8 0

2 years ago

NEED HELP ASAP, WORTH 80PTS

sp2606 [1]

This is because the expression can be simplified to get the same result. -1+2log_4((1/4)x)

3 0

2 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST Part A: Create a fifth-degree polynomial with four terms in standard form. How do you know it is in stand

qwelly [4]

5x 3y^3 2z

I know it is in standard form because there are no more like terms.

Part B: Polynomials are always closed under multiplication. Unlike with addition and subtraction, both the coefficients and exponents can change. The variables and coefficients will automatically fit in a polynomial. When there are exponents in a multiplication problem, they are added, so they will also fit in a polynomial.

Or,

Refer to the photos:

hope this help :)

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2 years ago