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3 years ago

Solve the equation: 2^3·2^2

Mathematics

2 answers:

Anit [1.1K]3 years ago

8 0

Answer:

Two ways to do this:

Multiply the exponents first to get 2^5 then simplify to get 32.

Simplfy 2^3 (8) and 2^2. Then multiply 8 and 4 together to get 32.

Hope that helps!

torisob [31]3 years ago

3 0

Answer:

Step-by-step explanation:

$2^3 * 2^2\\8 * 4\\32$

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Which expression is equivalent to 4 sqrt 24x^6y/128x^4y^5

Stels [109]

The first step for finding out if the expression provided is equivalent to $\sqrt{4}$ is to reduce the fraction with $x^{4}$ .
$\frac{24 x^{2} y}{128 y^{5} }$
Now reduce the fraction with y.
$\frac{24 x^{2} }{128 y^{4} }$
Finally,, reduce the fraction with 8 to get your final answer.
$\frac{3 x^{2} }{16 y^{4} }$
Let me know if you have any further questions.
:)

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3 years ago

Which property is used in the following expression ? (a x b) x c = a x (b x c)

Firlakuza [10]

A- Associative Property of Multiplication

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3 years ago

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Please please please help me

Fiesta28 [93]

Answer:

4x and 5.9

Step-by-step explanation:

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3 years ago

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If a storm window has an area of 640 square inches, what is the equation to find the dimensions when the window is 20 inches hig

Strike441 [17]

<span>x(x-20)=640

Hope that helps!</span>

5 0

3 years ago

Please help i will mark brainliest

Evgen [1.6K]

Answer:

2. $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

$\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]$ = $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. This matrix requires for the matrices to be multiplied first, then added.

$\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]$ + $\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. Here we can add the last 2 matrices to find x.

$\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]$ + $\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]$ = $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Hope this helps! (Please consider giving brainliest)

4 0

3 years ago