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3 years ago

Please please help me

Mathematics

2 answers:

Murljashka [212]3 years ago

8 0

Answer:

Choice B

Step-by-step explanation:

The bottom right angle is 80° since thats the value of its complement

Subtract 180-123 to get the complement of the bottom left and the value of the bottom left, 57°

Since all the interior angles in a triangle will add up to 180° add 57 and 80 to get 137 then subtract 137 to get the value of x, 43.

ohaa [14]3 years ago

7 0

Answer:

b) 43 degrees

Step-by-step explanation:

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An Internet store charges a base fee plus $1.50 per pound to ship items. The table shows samples of their shipping rates.

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Answer: For Last Question 4.50

Step-by-step explanation:It depends on the price per pound. Let's say the price per pound is 50 cents (or 0.50). (This is an example, the answer I'm giving will most likely NOT be correct, due to the nature of your question - sorry!) To calculate the price of Derek's package, you would multiply 7 (the weight of the package) by 0.50 (the price per pound), which totals to 3.50 Next, to calculate the price for Keisha's package, you'd do the same thing, but instead of multiplying 7 by the price per pound, you would multiply 10 by the price per pound, or 0.50. This multiplies out to 5 dollars. Next you'd subtract Derek's price from Keisha's, which is 5 - 3.50 or 1.50. If it is asking for a percentage, it would be about 150%.

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Two friends, Damian and Nicole, took summer jobs. The equation y = 15.52

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2 years ago

41% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

lys-0071 [83]

Answer:

a) 0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

b) 0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

c) 0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have very little confidence in newspapers, or they do not. The answers of each adult are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

41% of U.S. adults have very little confidence in newspapers.

This means that $p = 0.41$

You randomly select 10 U.S. adults.

This means that $n = 10$

(a) exactly five

This is $P(X = 5)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.41)^{5}.(0.59)^{5} = 0.2087$

0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

(b) at least six

This is:

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.41)^{6}.(0.59)^{4} = 0.1209$

$P(X = 7) = C_{10,7}.(0.41)^{7}.(0.59)^{3} = 0.0480$

$P(X = 8) = C_{10,8}.(0.41)^{8}.(0.59)^{2} = 0.0125$

$P(X = 9) = C_{10,9}.(0.41)^{9}.(0.59)^{1} = 0.0019$

$P(X = 10) = C_{10,10}.(0.41)^{10}.(0.59)^{0} = 0.0001$

Then

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.1209 + 0.0480 + 0.0125 + 0.0019 + 0.0001 = 0.1834$

0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

(c) less than four.

This is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.41)^{0}.(0.59)^{10} = 0.0051$

$P(X = 1) = C_{10,1}.(0.41)^{1}.(0.59)^{9} = 0.0355$

$P(X = 2) = C_{10,2}.(0.41)^{2}.(0.59)^{8} = 0.1111$

$P(X = 3) = C_{10,3}.(0.41)^{3}.(0.59)^{7} = 0.2058$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0051 + 0.0355 + 0.1111 + 0.2058 = 0.3575$

0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

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3 years ago

Help! I do not understand a single thing lol I’m sorry<3

kati45 [8]

= 8

step-by-step explanation:

evaluate 

-8c⁴ d +4c² d² + 16c - 2d

<h2 />

when c =-1 ,d=4

=8

<h2>hope it helps!</h2>

#carry on learning

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I don't need the work just the answer!!

kaheart [24]

I believe that it’s y=5x

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