The factorization if the given expression 128 + 2d³ is 2(64 + d³).
<h3>Factorization</h3>
128 + 2d³
There are two parameters in the expression;
The common factors between 128 and 2d³ is 2
So,
128 + 2d³
= 2(64 + d³)
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Answer:
8% probability that he or she actually has the disease
Step-by-step explanation:
We use the Bayes Theorem to solve this question.
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?
This means that:
Event A: Test comes back positive.
Event B: Having the disease.
Test coming back positive:
2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that 
For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.
Then

Finally:

8% probability that he or she actually has the disease
This triangle is classified as a right triangle because it contains one right angle (90 degrees).
An obtuse triangle is given that classification when one of the angles is greater than 90 degrees.
An acute triangle is any triangle that has all 3 angles less than 90 degrees.