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3 years ago

Pls helppp I’ll brainlest

Mathematics

2 answers:

tankabanditka [31]3 years ago

6 0

Answer:

Option B

Step-by-step explanation:

minus is represented as an expression

jolli1 [7]3 years ago

5 0

Answer:

its D

Step-by-step explanation:

BRANILEST!?!?!?!?!?!?

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

Read 2 more answers

Solving Exponential Equations (lacking a common base)<br> 31^d=38

Bond [772]

Answer:

d = log 38/log31

d = 1.06

Step-by-step explanation:

31 ^ d = 38

Take log of both sides since the exponential equation have different base (always)

d log 31 = log 38

d = log 38 / log 31

d = 1.58 / 1.491

d = 1.06.

We can actually check to see if this is correct.

Substituting d = 1.06

31^ 1.06 = 38.092

(You see, that's approximately correct)

Keep learning, maths is fun!

8 0

3 years ago

The average distance from Earth to the sun is about 9.3×10^7 miles. The average distance from Mars to the sun is about 1.4×10^8

diamong [38]

Move the decimal to the right (you go to the right since the exponent is positive, if the exponent was negative then you would move left) seven times, giving you 9,300,000 miles (for Earth). You then do the same with the next equation, giving you 140,000,000 miles (for Mars).

Finally, to find the official number of miles, you simply work the equation 140,000,000 - 9,300,000 .. giving you 130,700,000 miles.

If your teacher wants you to put it back into exponential form, then you first make the number into a decimal that is greater than one and less than ten.

1.30700000

Then, what you want to do is count all of the zeros as a single exponent, giving you 5, but we're not done yet. To get the correct answer, you have to also count the numbers until you reach the decimal. Remember to take out the zeros, because they're not really necessary anymore!

1.307× $10^{8}$