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V125BC [204]
3 years ago
11

What is the approximate value of x in the diagram below?

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
6 0

Answer:

The approximate value of x in the diagram is 39.59

Step-by-step explanation:

erastova [34]3 years ago
5 0
There's no diagram! link it and i'll help :)
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What is the first term in this expansion? a 2x15 b 215x15 c 10y15 d 1015y15
Oduvanchick [21]

Answer:

2^15x^15 is the correct answer.

Step-by-step explanation:

8 0
3 years ago
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David lives 3 2/3 miles from the lake. Mariel lives2 1/2 times as far from the lake as David does.
jek_recluse [69]
(3 + (2/3))(2+(1/2) = 3*2+2*(2/3)+3*(1/2)+((2/3)(1/2)) = 6+(4/3) +(3/2) + (2/6) = 6 + ((8+9+2)/6) = 6 + (19/6) = 6 + 3 + 1/6 = 9 + 1/6 miles = D
3 0
3 years ago
Please help with the following question
sasho [114]
  We have:
  The generic equation of the line is:  y-yo = m (x-xo)
  The slope is:
  m = (y2-y1) / (x2-x1)
  m = (- 2-0) / (3-0)
  m = -2 / 3
  We choose an ordered pair
  (xo, yo) = (0, 0)
  Substituting values:
  y-0 = (- 2/3) (x-0)
  Rewriting:
  y = (- 2/3) x
  Answer:
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5 0
3 years ago
One sample has Aa Aa One sample has n 10 scores and a variance of s2 20, and a second sample has n 15 scores and a variance of s
siniylev [52]

Answer:

option (a) It will be closer to 30 than to 20

Step-by-step explanation:

Data provided in the question:

For sample 1:

n₁ = 10

variance, s₁² = 20

For sample 2:

n₂ = 15

variance, s₂² = 30

Now,

The pooled variance is calculated using the formula,

S^{2}_{p} = \frac{(n_{1}-1)\times s^{2}_{1} +(n_{2}-1)\times s^{2}_{2}}{n_{1}+n_{2}-2}

on substituting the given respective values, we get

S^{2}_{p} = \frac{(10-1)\times 20 +(15-1)\times 30}{10+15-2}

or

S^{2}_{p} = 26.0869

Hence,

the pooled variance will be closer to 30 than to 20

Therefore,

The correct answer is option (a) It will be closer to 30 than to 20

4 0
3 years ago
For what value of c does the following system have no solution?<br><br> 1/2x+1/5y=2<br> 5x+2y=c
Minchanka [31]

Answer:

Step-by-step explanation:

\frac{1}{2}x+\frac{1}{5}y = 2 \mid 5x + 2y = c

First let's multiply the 1st equation by 10.

5x + 2y = 20 \mid 5x + 2y = c

So, we can see that the equations have the same coefficients and that implies  they are equal.

So the equation has no solutions for. c \in R \setminus{20}

3 0
3 years ago
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