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2 years ago

At one time will the hour and minute hand of a clock form a 105 degree angle?

2 answers:

Taya2010 [7]2 years ago

8 0

A clock is really just a circle, and a circle has 360 degrees in total. If we divide that by 12, which is how many hours there are on the clock, we get 30. Therefore, every hour represents 30 degrees of the 360. If we divide 105 by 30, we will get 3 and some remainder. This means that if the hour hand is at 12, then the minute hand has to be farther than the 3.

The remainder is 15, which is half of 30 so the minute hand would be halfway between the 3 and the 4, meaning the time would be 12:17, 30 seconds. Hope this helps!

Eddi Din [679]2 years ago

4 0

11:15 would be the time.

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At which x-value does the cosine function attain a maximum value?.

Troyanec [42]

Answer:

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2 years ago

Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are rando

qwelly [4]

Answer: The probability that both televisions work is 0.5625 .

The probability at least one of the two televisions does not work is 0.4375.

Step-by-step explanation:

Given : Number of televisions received in shipment= 12

Number of defective televisions received in shipment= 3

Then proportion of defective televisions = $\dfrac{3}{12}=0.25$

Using binomial probability formula, the probability of getting success in x trials is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

If two televisions are randomly selected, then the probability that both televisions work will be :-

$P(0)=^2C_0(0.25)^0(0.75)^2=(0.75)^2=0.5625$

The probability at least one of the two televisions does not work will be :-

$P(x\geq1)=1-P(0)=1-0.5625=0.4375$

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2 years ago

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2 years ago

Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

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2 years ago

A cylinder and a cone have congruent heights and radii. What is the ratio of the volume of the cone to the volume of the cylinde

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A cone with the same radius and height as a cylinder will have one-third the volume of the cylinder.

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Vcylinder = π*r^2*h

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2 years ago