(3 + (2/3))(2+(1/2) = 3*2+2*(2/3)+3*(1/2)+((2/3)(1/2)) = 6+(4/3) +(3/2) + (2/6) = 6 + ((8+9+2)/6) = 6 + (19/6) = 6 + 3 + 1/6 = 9 + 1/6 miles = D
Answer:
179.59
Step-by-step explanation:
.........................
Answer:
<em>estimated sales on Wednesday is 19000 pounds.</em>
<em></em>
Step-by-step explanation:
On Monday, he sold 25196 pounds. Estimated to the nearest thousand that is 25000 pounds.
On Tuesday, he sold 18023 pounds. Estimated to the nearest thousand, that is 18000 pounds
Wednesday's sales is unknown. We designate as x
All in all he sold 62409. Estimated to the nearest thousand, that is 62000
The sales on Monday, plus sales on Tuesday, plus sales on Wednesday, must all sum up to the total sales.
25000 + 18000 + x = 62000
43000 + x = 62000
x = 62000 - 43000 = 19000
therefore <em>estimated sales on Wednesday is 19000 pounds.</em>
Answer:
Relations B and E do not represent the function.
Step-by-step explanation:
We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.
In other words, we can not have duplicated inputs as there should be only 1 output for each input.
If we closely observe relation B, and E i.e.
- B) {(3,4), (4,5), (3,6). (6,7)}
Relation 'B' IS NOT A FUNCTION
Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.
Thus, relation B is NOT a function.
Relation 'E' IS NOT A FUNCTION
Relation E has duplicated or repeated inputs i.e. x = 4 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.
Thus, relation B is NOT a function.
Therefore, relations B and E do not represent the function.
