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Ulleksa [173]
3 years ago
13

the graph of the function y=x^(2) is reflected across the x-axis, then translated two units left and six units down, write and e

quation to represent the new functoin
Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer: -4,-2

Step-by-step explanation: Since it is reflected across the x- axis, translated two units left and six units down it would be -4, -2 because 2-6= -4

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I will give brainlest if you get it correct ​
lianna [129]

Answer:i think d.please dont blame me im not sure.sorry

Step-by-step explanation:

8 0
3 years ago
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How do I simplify (2k ^2 +5k-6) (3k-1)
wolverine [178]
(2k² + 5k - 6)(3k - 1)
(6k³ - 2k² + 15k² - 5k - 18k + 6)
6k² + 13k² - 23k + 6

Use the FOIL method to simplify the problem.
(FOIL stands for first outer, inner, last)
8 0
3 years ago
Ishaan is 222 times as old as Christopher. 353535 years ago, Ishaan was 777 times as old as Christopher.
klemol [59]
<h3><u>Question:</u></h3>

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?

<h3><u>Answer:</u></h3>

The present age of Christoper is 42 years old

<h3><u>Solution:</u></h3>

Given that Ishaan is 2 times as old as Christoper

Let the present age of Christoper be "x"

Then, Present age of Ishaan = 2 times as old as Christoper

present age of Ishaan = 2x

<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>

Age of Ishaan 35 years ago = Present age of Ishaan - 35

Age of Ishaan 35 years ago = 2x - 35

Similarly,

Age of christoper 35 years ago = Present age of christoper - 35

Age of christoper 35 years ago = x - 35

From given statement, 35 years ago, Ishaan was 7 times as old as Christopher

Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago

(2x - 35) = 7(x - 35)

<em><u>Solve the above equation for "x"</u></em>

2x - 35 = 7x - 245

2x - 7x = -245 + 35

-5x = -210

<h3>x = 42</h3>

Thus present age of Christoper is 42 years old

5 0
3 years ago
What is 2 units left 2 units up and 4 units right if you start at 0,0
elena-s [515]
That answer would be 2,2
5 0
3 years ago
Read 2 more answers
Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent
Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly  among the given student the probability that this student is wearing a ring or necklace is

P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1

P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

7 0
3 years ago
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