Can someone please help me pls

In 1911 Ernest Rutherford did a famous experiment using fast-moving alpha particles as bullets and very thin gold foil as a targ

Roman55 [17]

1. Atoms are mostly empty space

2. Atoms have a concentration of positive matter somewhere in them

3. The concentration of this positive matter is very small

7 0

2 years ago

3. give reasons

soldi70 [24.7K]

Answer:

A.A gas exerts pressure on the walls of the container. Reason: They have high kinetic energy and negligible force of attraction to move constantly moving with high speed in all directions. ... These collisions of the gas particles with the container walls exert pressure on the walls of the container.

B A gas exerts pressure on the walls of the container due to imapact of its gas molecules with hight velocity .

C.A wooden table should be called a solid. Reason: It has a definite shape and volume. It is very rigid and cannot be compressed, i.e., it has a solid characteristic.

D.We can easily move our hand in air but to do the same through a solid block of wood we need a karate expert. It is because the molecules of air has less force of attraction between them and a very small external force can separate them and pass through it.

Explanation:

Plz mark me as a brainlest

3 0

3 years ago

Not sure how to do this

faust18 [17]

Answer:

0.0991 M

Explanation:

Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.

H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O

Step 2: Calculate the moles of oxalic acid

The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:

$0.153g \times \frac{1mol}{90.03g} = 1.70 \times 10^{-3} mol$

Step 3: Calculate the moles of sodium hydroxide

The molar ratio of H₂C₂O₄ to NaOH is 1:2.

$1.70 \times 10^{-3} molH_2C_2O_4 \times \frac{2molNaOH}{1molH_2C_2O_4} = 3.40 \times 10^{-3} molNaOH$

Step 4: Calculate the molarity of sodium hydroxide

$\frac{3.40 \times 10^{-3} mol}{34.3 \times 10^{-3} L} = 0.0991 M$

4 0

4 years ago

Student prepares a 0.207 g sample of the nonvolatile solute caryophyllene by dissolving the substance in 1.00 g of chloroform (K

Sergeeva-Olga [200]

Answer: 204.2 g/mol

Explanation:

Elevation in boiling point is given by:

$\Delta T_b=k_b\times m$

$\Delta T_b$ = Elevation in boiling point = $3.68^0C/m$

$k_b$ = boiling point constant = $3.63^0C/m$

m = molality

$Molality=\frac{n\times 1000}{W_s}$

where,

n = moles of solute = $\text {given mass}{\text {molar mass}}=\frac{0.207}{M}$

$W_s$ = weight of solvent in g = 1g

Molality = $\frac{0.207\times 1000}{M\times 1g}$

Putting in the values we get,

$3.68=3.63\times \frac{0.207\times 1000}{M\times 1g}$

$M=204.2g/mol$

The molar mass of caryophyllene is 204.2 g/mol.

5 0

3 years ago

A 13.58 g sample of a compound contains 8.67 g of iron, Fe, 1.60 g of phosphorus, P, and oxygen, O. Calculate the empirical

antiseptic1488 [7]

Answer:

$Fe_3PO_4$

Explanation:

To do this, we find the moles of each element. We get around 0.155 moles of Fe, 0.051 moles of P, and 0.206 moles of O. We then divide each one by the smallest one (which is 0.051 moles of P). We then get 3 for Fe, 1 for P, and 4 for O. This correlates to the empirical formula of the compound.

6 0

4 years ago