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rjkz [21]
2 years ago
7

In 1911 Ernest Rutherford did a famous experiment using fast-moving alpha particles as bullets and very thin gold foil as a targ

et. The results of this experiment showed that:
Chemistry
1 answer:
Roman55 [17]2 years ago
7 0
1. Atoms are mostly empty space

2. Atoms have a concentration of positive matter somewhere in them

3. The concentration of this positive matter is very small
You might be interested in
If the compound has a molar mass of 156 g/mol, what is its molecular formula?
oksano4ka [1.4K]
I believe that the choices for this question are:
C2H4O2, C4H8O4 CH2O, C6H12O6 C3H6O3, C6H12O6 C2H4O2, C6H12O6 
 
The answer to this based on the molar masses given is:
C2H4O2, C6H12O6 
 
To prove calculate the molar mass:
C2H4O2 = 2*12 + 4*1 + 2*16 = 60
C6H12O6 = 6*12 + 12*1 + 6*16 = 180
3 0
3 years ago
1. A sample of oxygen is collected over water at 22 ° C and 762 torr. What is the partial pressure of the dry oxygen? The vapor
Rom4ik [11]

Answer: The partial pressure of the dry oxygen is 742 torr

Explanation:

Dalton's Law of Partial Pressure states that the total pressure exerted by a mixture of gases is the sum of partial pressure of each individual gas present. Thus P(total)=P_1+P_2 .........

Given; Total pressure = 762 torr

partial pressure of water = 19.8 torr

partial pressure of dry oxygen = ? torr

Total pressure  = partial pressure of water + partial pressure of dry oxygen

762 torr = 19.8 torr = partial pressure of dry oxygen

partial pressure of dry oxygen = 742 torr

The partial pressure of the dry oxygen is 742 torr

8 0
4 years ago
Please help me I don't know these.
blagie [28]
Add x on all of them I just took what ur taking rn !!!!!
4 0
3 years ago
Read 2 more answers
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

6 0
4 years ago
Which substance is a strong electrolyte?
zavuch27 [327]
Some are:

NH4Cl
KOH
HCl
6 0
3 years ago
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