Answer:
Magnitude = 1.51 ×10^6m/s
Direction is to the north
Explanation:
Question:
If an electron in an electron beam experiences a downward force of 2.0 × 10^-14N while traveling in a magnetic field of 8.3 × 10^-2T to the west, what is the direction and magnitude of the velocity?
Solution:
F= 2.0 × 10^-14N
Magnetic force = B = 8.3 × 10^-2T
Let the charge, q= 1.6×10^-19
F = Bqvsinθ
v = F/(Bqsinθ)
v = 2×10^-14/(8.3 × 10^-2 × 1.6×10^-19 ×sin90)
v = 2×10^-14/(13.28×10^-21 × 1)
v = 2/13.28 × 10^-14/10^-21
v = 0.1506 × 10^(-14+21)
v = 0.1506 × 10^7 = 0.151 × 10^7
v = 1.51 ×10^6m/s
Force is going down
magnetic field points west
Using the right and rule:
Point your fingers towards the west, and your thumb will point north. Since this is an electron, use the back of your hand( turn your hand backwards). The thumb points north.
Velocity direction is north
