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Tresset [83]
3 years ago
11

Rewrite the function, differentiate, and then simplify y= 3/√x

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

\frac{dy}{dx} = - \frac{3}{2x^{\frac{3}{2} } }

Step-by-step explanation:

Differentiate using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1}

Given

y = \frac{3}{\sqrt{x} } = 3x^{-\frac{1}{2} } , then

\frac{dy}{dx} = - \frac{3}{2} x^{-\frac{3}{2} } = - \frac{3}{2x^{\frac{3}{2} } }

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What is the gcf of 36, 126, and 210?
Artyom0805 [142]

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I have a stamp collection. 70% of my stamps are Canadian and 30% are international. I have 500 more Canadian stamps than interna
shutvik [7]

Answer: N= 375, C= 875

Step-by-step explanation:  Let Canadian stamps=C

Let International stamps=N

C=875     and        N=375

 

C - 500=N,  .70(N + C) =C

Solve the following system:

{C-500 = N |     (equation 1)

0.7 (C+N) = C |     (equation 2)

Express the system in standard form:

{-N+C = 500 |     (equation 1)

0.7 N-0.3 C = 0 |     (equation 2)

Add 0.7 × (equation 1) to equation 2:

{-N+C = 500 |     (equation 1)

0 N+0.4 C = 350 |     (equation 2)

Divide equation 2 by 0.4:

{-N+C = 500 |     (equation 1)

0. N+C = 875. |     (equation 2)

Subtract equation 2 from equation 1:

{-N+0 C = -375. |     (equation 1)

0 N+C = 875. |     (equation 2)

Multiply equation 1 by -1:

{N+0 C = 375. |     (equation 1)

0 N+C = 875. |     (equation 2)

Collect results:

Answer: |  N = 375        and             C=875

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3 years ago
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q + d = 16
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q = 10...quarters

so there are (10 - 6) = 4 more quarters then dimes
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